Step-by-step explanation:
The digital scale has to be used once.
Let the coins that have normal weights are normal coins and the coins that has a weight 1 pound less are called defected coins.
5 stacks are there in which any four contains normal coins and 1 stack contains defected coins.
Took 1 coin from 1st stack, 2 coins from 2nd stack and so on..
Weigh the coins and see the result.
<u>If the total weight is 1 pound less than the stack 1 contains defected coin.</u>
<u>If the total weight is 2 pounds less than the stack 2 contains defected coin.</u>
<u>If the total weight is 3 pounds less than the stack 3 contains defected coin.</u>
<u>If the total weight is 4 pounds less than the stack 4 contains defected coin.</u>
<u>If the total weight is 5 pounds less than the stack 5 contains defected coin.</u>
yes or no I am not very sure
[x-1]=5x+10
We have two equations:
1) x-1=5x+10
x-1=5x+10
x-5x=10+1
-4x=11
x=-11/4
2) x-1=-(5x+10)
x-1=-(5x+10)
x-1=-5x-10
x+5x=-10+1
6x=-9
x=-9/6=-3/2
we have two possible solutions:
solution₁; x=-11/4
solution₂: x=-3/2
we check it out:
1) x=-11/4
[x-1]=5x+10
[-11/4 - 1]=5(-11/4)+10
[(-11-4)/4]=-55/4 + 10
[-15/4]=(-55+40) /4
15/4≠-15/4 This solution don´t work.
2) x=-3/2
[x-1]=5x+10
[-3/2 - 1]=5(-3/2)+10
[(-3-2)/2]=-15/2 + 10
[-5/2]=(-15+20)/2
5/2=5/2; this solution works.
Therefore:
Answer: x=-3/2.
Answer:20
Step-by-step explanation:
