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ycow [4]
2 years ago
12

Solve for x. please explain in detail

Mathematics
1 answer:
Sholpan [36]2 years ago
6 0

Use the cosine formula

Cos(angle) = adjacent/ hypotenuse


cos(30) = x/8

Cos(30) can be written as sqrt(3)/2

Now you have :

sqrt(3)/2 = x/8

Multiply both sides by 8:

X = sqrt(3)/2 x 8

Simplify:

X = 4sqrt(3)

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Stacy spent £20 on ingredients for bread.
Liula [17]

Answer:

Stacy made £25.2 from the 18 loaves of bread. So She made £5.20 as a profit.

Step-by-step explanation:

18 loaves of bread × £1.4 = £25.2 Round it up = £25

£25.20 - £20 = £5.20 Round it up = £5

Stacy Made about £5 as profit.

8 0
3 years ago
7+ 2x divided by 5= 13
Troyanec [42]

Answer:

x=29

Step-by-step explanation:

Given equation :

\frac{(7+2x)}{5} =13

Making the terms of 'x' to one side and constants to the other.

                   (7+2x)=13*5

                       7+2x=65

                            2x=65-7

                              2x=58

                                x=\frac{58}{2}

                                  x=29

So, the value of 'x' is 29.

4 0
3 years ago
Read 2 more answers
Jose bought a magazine for $6 and five notepads. He spent a total of $26. How much did each notepad cost?
bixtya [17]
4 dollars. 26-6=20. 20/5=4
8 0
3 years ago
Which of the following are adjacent angles?
andriy [413]

Answer:

c

Step-by-step explana i think its right

3 0
3 years ago
On a map, the distance between two historical markers is 4.5 inches, and 2.5 inches represents 10 miles.
Morgarella [4.7K]

Answer:

The actual distance between the historical markers is 18 miles.

Step-by-step explanation:

Given : On a map, the distance between two historical markers is 4.5 inches, and 2.5 inches represents 10 miles.  

To find : What is the actual distance between the historical markers?

Solution :

We have given that,

2.5 inches represents 10 miles.

i.e, 1 inch represent \frac{10}{2.5} miles.

1 inch = 4 miles.

Now, The distance between two historical markers is 4.5 inches.

The actual distance between the historical markers in 4.5 inch is

4.5 \text{ inch}=4.5\times 4\text{ miles}

4.5 \text{ inch}=18\text{ miles}

Therefore, The actual distance between the historical markers is 18 miles.

7 0
4 years ago
Read 2 more answers
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