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stealth61 [152]
3 years ago
10

What’s the answer? I really need help I been trying for the longest.

Mathematics
2 answers:
sesenic [268]3 years ago
6 0

Answer:

The answer 8.

lookie here 7/4 is 1.75 so take that and divide 14 by 1.75 and you get 8 but another way is divide 14 by 7 which is 2 so multiply 4 by 2 and ya got 8.

nikitadnepr [17]3 years ago
5 0
D. 8

you cross multiply. so 14x4=56
then divide 56 by 7 to get 8
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Several terms of a sequence {an}n=1 infinity are given. A. Find the next two terms of the sequence. B. Find a recurrence relatio
s344n2d4d5 [400]

Answer:

A)\frac{1}{1024},\frac{1}{4096}

B) \left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.

C) \\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...

Step-by-step explanation:

1) Incomplete question. So completing the several terms:\left \{a_{n}\right \}_{n=1}^{\infty}=\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},... \right \}

We can realize this a Geometric sequence, with the ratio equal to:

q=\frac{1}{4}

A) To find the next two terms of this sequence, simply follow multiplying the 5th term by the ratio (q):

\frac{1}{256}*\mathbf{\frac{1}{4}}=\frac{1}{1024}\\\\\frac{1}{1024}*\mathbf{\frac{1}{4}}=\frac{1}{4096}\\\\\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\mathbf{\frac{1}{1024},\frac{1}{4096}}\right \}

B) To find a recurrence a relation, is to write it a function based on the last value. So that, the function relates to the last value.

\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.

C) The explicit formula, is one valid for any value since we have the first one to find any term of the Geometric Sequence, therefore:

\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...

6 0
3 years ago
The temperature in Yarmouth is 6.5 C. In Sydney it is 8C colder. What is the
lukranit [14]
If Yarmouth is 6.5C and Sydney is 8C colder you would just subtract.
6.5-8=-1.5C
4 0
3 years ago
The problem is 14?minus 85
denpristay [2]

Answer:

-71, and also 71

Step-by-step explanation:

It's Simple Subtraction or if your doing 85-14 its gonna be 71

3 0
4 years ago
Determine if each graph below represents a function. Then state its domain and range. PLEASE HELP!!!! WILL MARK BRAINLIEST. NEED
Montano1993 [528]

Answer: Graph 10 and 12 are both functions while graph 13 is not a function

Step-by-step explanation: The best way to know if the graph is a function is by the vertical line test, if the points on the graph pass through the straight vertical line more than once, it is not a function, but if it passes though the line only once then it is a function. Now for the Domain and range, the best way to see it is as DomainX and RangeY, this is something I learned when I did functions, and it helped me a lot. Now if you look at 10 and 12, both go on infinitely, as they have no stopping point, meaning that the domain would be (-infinity, infinity), and for 13 you can simply put the coordinates for each point in a chart, with your X and Y, remember DomainX and RangeY, this should help you understand which is X and which is Y. I hope this helped a bit. Now for RangeY, for 10, look for the lowest number in the Y axis that the line goes, for this case its, -1, and then look for the highest number on the Y axis that the line goes, aka 3, now use this as a example and you can easily find 12's Range.

4 0
4 years ago
Please help in maths
diamong [38]

Answer:8124

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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