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11Alexandr11 [23.1K]

2 years ago

11

there are 32 children in my class fun size treats come in bags of 20.what is the smallest number of bags .I must buy so that eac

h child has the same number of treats?

1 answer:

AfilCa [17]2 years ago

8 0

If you buy 5 bags each kid can get 3 pieces of candy . Or you can buy 4 bags and each kid can have two

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If there is 100 students how much would 40% be

I am Lyosha [343]

Answer: 40 students.

Step-by-step explanation:

To solve this problem you mmust apply the steps shown below:

1. You know that there is a total of 100 students, then you can say that the 100% is 100 students.

2. Then, to calculate how much would 40% be, you must multiply 100 students by 40% which you rewrite as a decimal by dividing it by 100, as following:

40%/100=0.4

Then 40% of the students would be

100 studens*0.4=40 students

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3 years ago

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3 to the 2 power plus (9-5)

QveST [7]

Answer:

${3}^{2} + (9 - 5) \\ = 9 + 4 \\ = 13$

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2 years ago

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The quotient of a number y and 22

Stels [109]

Y/22 would be the answer to your question.

4 0

3 years ago

Julli [10]

Answer:

The values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

Step-by-step explanation:

Given:

The equation to solve is given as:

$5x^5+6x^4+80x^3+96x^2=0$

Factoring $x^2$ from all the terms, we get:

$x^2(5x^3+6x^2+80x+96)=0$

Now, rearranging the terms, we get:

$x^2(5x^3+80x+6x^2+96)=0$

Now, factoring $5x$ from the first two terms and 6 from the last two terms, we get:

$x^2(5x(x^2+16)+6(x^2+16))=0\\x^2(x^2+16)(5x+6)=0$

Now, equating each factor to 0 and solving for 'x', we get:

$x^2=0\\x=0\ and\ 0\\\\5x+6=0\\x=\frac{-6}{5}=1.2\\\\x^2+16=0\\x^2=-16\\x=\sqrt{-16}=\pm 4i$

There are 3 real values and 2 imaginary values. The value of 'x' as 0 is repeated twice.

Therefore, the values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

4 0

3 years ago

The diagram below represents the net of a triangular prism. What is the surface area of the triangular prism?

AleksandrR [38]

Answer:

(C)

Step-by-step explanation:

The diagram is divided ninto 5 parts that is rectangles ABCD, CHGD, GFEH and triangles CIH and DGJ.

Area of rectangle ABCD= $l{\times}b$

= $12{\times}6=72cm^{2}$

Area rectangle CDHG= $l{\times}b$

= $12{\times}8=96cm^{2}$

Area rectangle HGFE= $l{\times}b$

= $10{\times}12=120cm^{2}$

Area of triangles CIH and DIG= $2{\times}\frac{1}{2}{\times}b{\times}h$

= $6{\times}8=48cm^{2}$

Surface area of the triangular prism=Area of rectangle ABCD+Area rectangle CDHG+Area rectangle HGFE+Area of triangles CIH and DIG

= $72+96+120+48=336cm^{2}$

Hence, option C is correct.

3 0

3 years ago