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OleMash [197]
2 years ago
9

A car can go 420 miles on a tank of gas (15 gallons in a tank). How many kilometers can this car go on 6.5 gallons

Mathematics
1 answer:
azamat2 years ago
3 0

Answer:

182 miles

Step-by-step explanation:

15 gallons -------------------------  420 miles

1 gallons --------------------------- 420/15 miles

1 gallons   ---------------------------  28 miles

6.5 gallons  -------------------------- 6.5 × 28 miles

6.5 gallons  --------------------------  182 miles

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  • Answer:\beta \beta \beta \beta \beta \beta \beta\frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} \frac{x}{y} x^{2} x^{2} x^{2} \alpha \alpha

Step-by-step explanation:

4 0
1 year ago
For parallelogram LMNO , if m
natali 33 [55]
I'm just going to assume you're given the volume and LMNO are sides of the parallelogram

Area = LMNO

M=?

M= \frac{area}{LNO}


5 0
3 years ago
Need help on this quiz​
Setler [38]

Answer:

it would be C.

Step-by-step explanation:

3 0
3 years ago
Let P(x) = F(x)G(x) and Q(x) = F(x)/G(x), where F and G are the functions whose graphs are shown.
bearhunter [10]
(a) We use product rule here. P'(x) = F'(x)G(x) + F(x)G'(x).P'(2) = F'(2)G(2) + F(2)G'(2). Looking at the graph: F'(2) = 0, F(2) = 3, G'(2) = 1/2, G(2) = 2. Hence, P'(2) = (0)(2) + (3)(1/2) = 1.5.
(b) Using the quotient rule here. Q'(x) = (G(x)F'(x) - F(x)G'(x))/G(x)^2. Looking at the graph: F'(7) = 1/4, F(7) = 5, G'(7) = -3/2, G(7) = 1. Q'(7) = (1*1/4-5*(-3/2))/1^2 = 31/4 = 7.75.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
HELP FAST!! WILL GIVEV BRAINLIEST
Alekssandra [29.7K]

Answer:

-2, -4, -1.5

Step-by-step explanation:

-6x+10>16

-6x>6

x<-1

(anything less than -1)

4 0
3 years ago
Read 2 more answers
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