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strojnjashka [21]

2 years ago

8

Trina is looking at a scale drawing with a scale of 4 inches = 200 miles. how can she simplify the scale to evaluate 1 inch on t

he drawing?

1 answer:

vivado [14]2 years ago

4 0

200/4 = 50

1 inch can be represented as 50 miles

Please like and brainliest

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Find the volume of the solid. Round your answer to the nearest tenth.

Sindrei [870]

Correct ~~~~~~~~~~~~~~~~~~~~~~

4 0

2 years ago

Sharon wants to start a savings account with the money she earns selling scented candles. She already has $50 and would like to

Romashka [77]

Answer:

She must sell as least 20 candles

Step-by-step explanation:

Sharon has 50 dollars

She makes 2 dollars per candle

Money in 50+2c

She needs at least 90

90≤ 50+2c

We need to solve this inequality

Subtract 50 from each side

90-50≤ 50-50+2c

40 ≤ 2c

Divide by 2

40/2 ≤ 2c/2

20 ≤ c

She must sell as least 20 candles

4 0

3 years ago

Read 2 more answers

What does this equal?

anzhelika [568]

It should be about 22.55.

4 0

3 years ago

How would I do this one?

viva [34]

First we would need to make a diagram, and from the given it would seem like it is a right triangle with the height as 760 ft. We have an angle given 89°18' which would need to be converted to degrees form, which is 89.3<span>°.

Now we would need to look for the ground distance, meaning the adjacent of the triangle. Since we have been given the angle and the height (which is the opposite side from the angle) we use the trigonometric function cotangent.

</span><span>760 Cot <span>[<span><span>(<span>89.3</span>)</span>∘</span>]</span>= 9.29 ft, that is the answer.</span>

6 0

2 years ago

Read 2 more answers

I need to know how to do the answer and why that’s the anwer

Pavel [41]

Ok so the answer is
$4 {x}^{2}$

so we multiply numbers that have the same variable

$2 {x}^{3} \: \: \times {2x}^{ - 1} \\ \\$
multiply 2 x 2

$2 \times 2 = 4$
then multiply the exponents

$x ^{3} \times x ^{ - 1}$
multipling like this will look like addition.
${x}^{3} \times {x}^{ - 1} = {x}^{2}$
so in other words you could do it like this too
${x}^{3} + {x}^{ - 1} = {x}^{2}$
now add the exponent with 4
$4 + {x}^{2} = 4x ^{2}$

now for the last part
${y}^{3} + {y}^{ - 3} = 0$
because -3 and 3 added together make 0
$0 + 4 {x}^{2} = 4 {x}^{2}$
I hope this help(it looks complicated but it's very easy and I hope I helped you out)

6 0

3 years ago