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3 years ago

The cost, c(x), for a taxi ride is given by c(x) = 2x + 4.00, where x is the

Mathematics

1 answer:

Alecsey [184]3 years ago

5 0

Answer:

Step-by-step explanation:

Because x represents the number of minutes so you multiply that by 2 then add 4 to get the total

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I need help.

saul85 [17]

Answer:

Hey you can login in Spain Server if you find difficulty here

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3 years ago

Write an equation for the graph shown in the form $y=ax b.$

Vedmedyk [2.9K]

The required straight equation will be y = -0.5x + 27.5 passes through the points (-5, 0) and (5, 2).

What are equations in a straight line?

A straight line's equation is given by y=mx+c, where c is the height at which the line intersects the y-axis (often referred to as the y-intercept) and m is the gradient.

According to the given graph,

We can see two points are (-5, 0) and (5, 2)

The linear equation will be: y - y₁ = (y₂ - y₁)/(x₂ -x₁ )[x -x₁]

Here

x₁ = -5, y₁ = 0

x₂ = 5, y₂ = 2

⇒ y - y₁ = (y₂ - y₁)/(x₂ -x₁ )[x -x₂]

Substitute values in the equation, we get

⇒ y - 0 = (2 - 0)/(8-4)(x-(-5))

⇒ y - 30 = (2)/(-4)(x + 5)

⇒ y - 30 = -1/2(x + 5)

⇒ y = (-1/2)x - 5/2 + 30

⇒ y = -0.5x + 27.5

Thus, the required equation will be y = -0.5x + 27.5 passes through the points (-5, 0) and (5, 2).

Learn more about straight line

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Write an equation for the graph shown in the form y=ax+b.

3 0

1 year ago

You _____ always prove a conclusion by inductive reasoning.

UNO [17]

Answer:

The answer is CANNOT (option b)

Step-by-step explanation:

4 0

3 years ago

What is the answer for 7•9-4(6+7)?

Anna35 [415]

THE ANSWER IS 11 100% RIGHT

3 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Crm%5Cfrac%7Bd%7D%7Bdx%7D%20%20%20%5Cleft%20%28%20%5Cbigg%28%20%5Cint_%7B1%7D%5E%7B%20%7B

Margaret [11]

Applying the product rule gives

$\displaystyle \frac{d}{dx}\int_1^{x^2}\frac{2t}{1+t^2}\,dt \times \int_1^{\ln(x)}\frac{dt}{(1+t)^2} + \int_1^{x^2}\frac{2t}{1+t^2}\,dt \times \frac{d}{dx}\int_1^{\ln(x)}\frac{dt}{(1+t)^2}$

Use the fundamental theorem of calculus to compute the remaining derivatives.

$\displaystyle \frac{4x^3}{1+x^4} \int_1^{\ln(x)}\frac{dt}{(1+t)^2} + \frac{1}{x(1+\ln(x))^2}\int_1^{x^2}\frac{2t}{1+t^2}\,dt$

The remaining integrals are

$\displaystyle \int_1^{\ln(x)}\frac{dt}{(1+t)^2} = -\frac1{1+t}\bigg|_1^{\ln(x)} = \frac12-\frac1{1+\ln(x)}$

$\displaystyle \int_1^{x^2}\frac{2t}{1+t^2}\,dt=\int_1^{x^2}\frac{d(1+t^2)}{1+t^2}=\ln|1+t^2|\bigg|_1^{x^2}=\ln(1+x^4)-\ln(2) = \ln\left(\frac{1+x^4}2\right)$

and so the overall derivative is

$\displaystyle \frac{4x^3}{1+x^4} \left(\frac12-\frac1{1+\ln(x)}\right) + \frac{1}{x(1+\ln(x))^2} \ln\left(\frac{1+x^4}2\right)$

which could be simplified further.

5 0

2 years ago