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Ronch [10]
3 years ago
7

The cost, c(x), for a taxi ride is given by c(x) = 2x + 4.00, where x is the

Mathematics
1 answer:
Alecsey [184]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Because x represents the number of minutes so you multiply that by 2 then add 4 to get the total

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Your bank statement shows that you have a balance of $412.20. All the checks you have written during this statement period are o
mina [271]
Missing check = $412.20 - $331.60 = $80.6


Hope it helps!

3 0
3 years ago
Charmaine pumped 42 gallons of water out of her pool. This was done over a period of 7 minutes at a constant rate. What was the
Mariana [72]
The answer is 6 bc take 42 divided by 7 = 6
7 0
2 years ago
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The table shows transactions from five different bank accounts. Fill in the missing numbers.(IMAGE ATTACHED)
DerKrebs [107]

Answer:

80

64

-175

Step-by-step explanation:

512-432=80

52+12=64

75+-100=-175

7 0
3 years ago
I put the wrong screenshot lol this is the last one for 25
hjlf

Answer:

The best way to measure an angle is to use a protractor. To do this, you'll start by lining up one ray along the 0-degree line on the protractor. Then, line up the vertex with the midpoint of the protractor. Follow the second ray to determine the angle's measurement to the nearest degree

Step-by-step explanation:

<h2>thankuuuu,☺</h2>
8 0
2 years ago
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Use the substitution of x=e^{t} to transform the given Cauchy-Euler differential equation to a differential equation with consta
kherson [118]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dt}=x\dfrac{\mathrm dy}{\mathrm dx}

which follows from x=e^t\implies t=\ln x\implies\dfrac{\mathrm dt}{\mathrm dx}=\dfrac1x.

\dfrac{\mathrm dy}{\mathrm dt} is then a function of x; denote this function by f(x). Then by the product rule,

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dt}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac1x\dfrac{\mathrm df}{\mathrm dx}

and by the chain rule,

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{\mathrm df}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}=\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dt^2}

so that

\dfrac{\mathrm d^2y}{\mathrm dt^2}-\dfrac{\mathrm dy}{\mathrm dt}=x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}

Then the ODE in terms of t is

\dfrac{\mathrm d^2y}{\mathrm dt^2}+8\dfrac{\mathrm dy}{\mathrm dt}-20y=0

The characteristic equation

r^2+8r-20=(r+10)(r-2)=0

has two roots at r=-10 and r=2, so the characteristic solution is

y_c(t)=C_1e^{-10t}+C_2e^{2t}

Solving in terms of x gives

y_c(x)=C_1e^{-10\ln x}+C_2e^{2\ln x}\implies\boxed{y_c(x)=C_1x^{-10}+C_2x^2}

4 0
3 years ago
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