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Ronch [10]
3 years ago
7

The cost, c(x), for a taxi ride is given by c(x) = 2x + 4.00, where x is the

Mathematics
1 answer:
Alecsey [184]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Because x represents the number of minutes so you multiply that by 2 then add 4 to get the total

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Can someone tell me the answer
Blizzard [7]
See the photo attached for the answers

7 0
3 years ago
2. Grades: 89.5 points/ 100 total is an A in school. If we have 530 total points this
Anton [14]

Answer: bruh just take one more test and get a 100% on it and then itll raise your grade to an A

Step-by-step explanation:

HOPE THIS HELPED MY G...

5 0
3 years ago
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A number that divided by 3 leaves 2, divided by 5 leaves 3 and divided by 7 leaves 2. What is the number?
Bogdan [553]
X/3=2 
x=6

x/5=3
x=15

x/7=2
x=14

Each time, you multiply both sides by the denominator.

Hope this helps :)
7 0
3 years ago
Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

8 0
1 year ago
ΔABC is a right triangle. Prove: a2 + b2 = c2 Right triangle BCA with sides of length a, b, and c. Perpendicular CD forms right
777dan777 [17]

Answer: Pythagorean Theorem Pieces of Right Triangles is not a justification for the proof.

Explanation : Here, \triangle ABC is a right triangle with sides a, b and c. Perpendicular CD forms right triangles BDC and CDA.

CD measures h units, BD measures y units, DA measures x units.

Draw an altitude from point C to Line segment AB Let segment BC = a segment CA = b, segment AB = c,  segment CD = h,  segment DB = y, segment AD = x,

y + x = c

a/c=y/a( Similarity theorem in triangles ABC and DBC )

a^2 = cy------(1) (Cross Product Property)

Similarly, b^2 = cx (Similarity theorem in triangles ABC and ADC)---------(2)

a^2 + b^2 = cy + cx(after adding equation (1) and (2) )

a^2 + b^2 = c(y + x)( By additional property of equality)

a^2 + b^2 = c^2. ( because y + x=c)

Thus, it has been proved that except Pythagorean Theorem Pieces of Right Triangles we use all other properties.

8 0
3 years ago
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