A= 1/360 pi r ^2
A= 252/360 pi 10^2
A= 70pi
Work shown above! Answer is 1 - cos(theta). Hope this helped C:
3x-2=x+2
2x=4
x=2
...............,
To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership. So set the no-membership cost equal to the yearly membership cost and solve.
no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day. So if we let d = number of days, our cost can be calculated by "7d"
a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"
Set them equal to each other and solve:
7d = 200 + 3d
4d = 200
d = 50
So you would need to attend the classes for at least 50 days to justify a yearly membership. I hope that helps!
No. If you make both denominators (aka the bottom number) the same, then you can see 3/4 is greater.
2/6=8/24
3/4=18/24