Answer: 219.52 inch^2
Step-by-step explanation:
Given the dimensions of rectangular papaerboard:
Length = 20inches
Width = 16inches
Area of rectangle = Length × width
Area of rectangle = 20 × 16 = 320 in^2
Area of a circle = pi*r^2
Therefore, area of semicircle = (pi*r^2) / 2
Diameter of circle = width of rectangle = 16 inches
Radius = diameter / 2 = 16 /2 = 8inches
Therefore, area of semicircle = (pi*8^2) / 2
= (3.14 × 64) / 2
= 200.96 / 2
= 100.48 inch^2
Therefore, area of paperboard left :
Area of rectangle - area of semicircle
320 - 100.48
= 219.52 inch^2
The answer is 0.625 because 1 mm=0.001 meter.
Steps:
10x50=500
500x1.25=625
Convert from mm to meters.
It would just be y=3600 I believe. Don’t overthink it bud
Answer:
755,160 ways
Explanation:
We're told that 31 cars are in a race.
Considering the order in which the cars can finish in the top 4 positions, any of the 31 cars can finish in the first position, any of the remaining 30 cars can finish in the second position, any of the remaining 29 cars can finish in the third position and any of the remaining 28 cars can finish in the fourth position, so the different numbers of ways can be determined as seen below;
Answer:
The pair of triangles that are congruent by the ASA criterion isΔ ABC and Δ XYZ.
The pair of triangles that are congruent by the SAS criterion is Δ BAC and ΔRQP.
Step-by-step explanation:
Two triangles are congruent by ASA property if any two angles and their included side are equal in both triangles .In triangles Δ ABC and Δ XYZ the equal side 5 is between the two equal angles. So these triangles are congruent by ASA criterion.
Two triangles are congruent by SAS if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle .In triangles Δ BAC and ΔRQP. the included angles A and Q are equal and hence the triangles are congruent by SAS criterion.
