Please answer 8th grade math

The area, A, of a triangle is one-half the product of the triangle's base and height.

nordsb [41]

A = (1/2)(b * h)

It is 1/2 times the product (which is the end result of multiplication of two values), of base (b) times height (h)

7 0

3 years ago

Ella Buys a book and a pen for $14. The cost of the book is two dollars more than twice the cost of the pen. Write a system of l

Vilka [71]

Answer: The book costs $10 and the pen costs $4✔️

Step-by-step explanation:

Let B the cost of the book and let P the cost of the pen.

Then we know:

The book and the pen cost $14:

B + P = $14 } Equation 1

We also know:

The cost of the book is two dollars more than twice the cost of the pen.

B = 2P + $2 } Equation 2

Now we can substitute the value of B from the equation 2 in the equation 1:

2P + $2 + P = $14

3P = $14 - $2 = $12

P = $12/3 = $4 , cost of the pen

Since we know the value of B from the equation 2, we can calculate B:

B = 2P + $2 = 2x$4 + $2 = $8 + $2 = $10 , cost of the book

Answer: The book costs $10 and the pen costs $4✔️

<h3>Verify </h3>

We can substitute these values in equations 1 and 2 and check the results:

B + P = $14 } Equation 1

$10 + $4 = $14 ✔️check!

B = 2P + $2 } Equation 2

$10 = 2x$4 + $2 = $8 + $2 = $10 ✔️check!

<h2>Spymore</h2>

5 0

3 years ago

Evaluate -3x^2-4x=-1

Butoxors [25]

Use the Quadratic formula,

x= -b +/- sqrt(b^2-4ac)
-------------------------
2a

x= 4 +/- sqrt(16+12)
----------------------
-6

x = 4+/- sqrt(28)
---------------
-6

x = 4 +/- 2*sqrt(7)
------------------
-6

x= 2(2+/- sqrt(7))
------------------
2(-3)

x= 2+/- sqrt(7)
--------------
-3

5 0

3 years ago

An exponential growth function has an asymptote of y = –3. Which might have occurred in the original function to permit the rang

Blababa [14]

The right choice is: A whole number constant could have been subtracted from the exponential expression.

Let be an exponential function of the form $y = A\cdot e^{B\cdot x}$ , where $A$ and $B$ are real numbers. A horizontal asymptote exists when $e^{B\cdot x} \to 0$ , which occurs for $B\cdot x \to - \infty$ .

For this function, the horizontal asymptote is represented by $y = 0$ and to change the value of the asymptote we must add the parent function by another real number ( $C$ ), that is to say:

$y = A\cdot e^{B\cdot x} + C$ (1)

In this case, we must use $C = -3$ to obtain an horizontal asymptote of -3. Thus, the right choice is: A whole number constant could have been subtracted from the exponential expression.