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Illusion [34]
2 years ago
7

How long is the tape for 30 mins

Mathematics
2 answers:
Marina CMI [18]2 years ago
6 0

Answer:

37,500 meters long

Step-by-step explanation:

The tape plays at 0.048 meters per second. First, let's find the number of seconds in 30 minutes.

  • 30 minutes
  • 60 seconds * 30
  • 1800 seconds

The tape plays at 0.048 meters per second for 1800 seconds

The equation is:

  • 0.048x = 1800
  • x = 1800/ 0.048
  • x = 37,500

The tape is \boxed{\text{37,500 meters long}}

-Chetan K

Lerok [7]2 years ago
4 0

Answer:

0.016

Step-by-step explanation:

u divide 0.048 by 30 and the result is the answer

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Sumiko and Chung are shopping. Chung wants to buy a video game that costs $60, and Sumiko wants to buy a new pair of sunglasses
vovangra [49]

Answer:

1.83

Step-by-step explanation:

First, add the game and glasses. Write down the number you just got. Now, multiply by 0.15.

Take the second away from the first.

Now multiply that by 0.087

Finally, take 20 away

That is how much money you have spent.

Use both savings so they both get a huge meal.

5 0
3 years ago
the smallest angle in a triangle is one-third of the largest angle. the third angle is 10degrees more than the smallest angle. f
Alex787 [66]
A: smallest 
c: largest
b: third 
a+b+c=180
a=c/3
b=10+a
solve it
a=34
b=44
c=102
5 0
3 years ago
How would the graph of the function y = r? - 8 be affected if the function were changed to y = x? - 3?
Leokris [45]
The graph would shift 5 units up
4 0
3 years ago
Parallelogram ABCD is rotated to create image A'B'C'D'. On a coordinate plane, 2 parallelograms are shown. The first parallelogr
Gala2k [10]

Answer:

(x,y)→(y,-x)

Step-by-step explanation:

Parallelogram ABCD:

A(2,5)

B(5,4)

C(5,2)

D(2,3)

Parallelogram A'B'C'D':

A'(5,-4)

B'(4,-5)

C'(2,-5)

D'(3,-2)

Rule:

A(2,5)→A'(5,-2)

B(5,4)→B'(4,-5)

C(5,2)→C'(2,-5)

D(2,3)→D'(3,-2)

so the rule is

(x,y)→(y,-x)

4 0
3 years ago
Read 2 more answers
If tan A = 4/3 and sin B = 45/53 and angles A and B are in Quadrant I, find the value of tan(A+B)
lbvjy [14]

Answer:

First, find tan A and tan B.

cosA=35 --> sin2A=1−925=1625 --> cosA=±45

cosA=45 because A is in Quadrant I

tanA=sinAcosA=(45)(53)=43.

sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.

sinB=1213 because B is in Quadrant I

tanB=sinBcosB=(513)(1312)=512

Apply the trig identity:

tan(A−B)=tanA−tanB1−tanA.tanB

tanA−tanB=43−512=1112

(1−tanA.tanB)=1−2036=1636=49

tan(A−B)=(1112)(94)=3316

kamina op bolte

✌ ✌ ✌ ✌

3 0
2 years ago
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