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miskamm [114]
3 years ago
8

Arthur drops a ball from a height of 81 feet above the ground. it’s height, , is given by the equation h=16ft^2+81, where t is t

he time in seconds. for which interval of the time is the height of the ball less than 17 feet
Mathematics
1 answer:
makvit [3.9K]3 years ago
5 0

Answer:

The height of the ball is less than 17 feet for t > 2 seconds.

Step-by-step explanation:

The height of the ball after t seconds is given by the following equation:

h(t) = -16t^{2} + 81

For which interval of the time is the height of the ball less than 17 feet

This is t for which:

h(t) < 17

So

-16t^{2} + 81 < 17

16t^{2} < -64

Multiplying by -1

16t^{2} > 64

t^{2} > \frac{64}{16}

t^{2} > 4

t > \sqrt{4}

t > 2

The height of the ball is less than 17 feet for t > 2 seconds.

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