To solve problems like this you can either graph or solve mathematically. To do the ladder we need to solve for one variable at a time. So lets cancel one variable out.
Multiply equation 1 by 2
This will give 4x-2y=14
Now we can get rid of y by subtracting 2 from 1
This will give x=9
Plug back in to either equation, i will use equation 2
3(9)-2y=5 simplify
-2y=-22 solve
Y=11
So i think in the school there may be 4800 in the school. Hope this helps
Consider the following two ordered bases of R2 R2: BC=={⟨1,2⟩,⟨3,5⟩},{⟨−1,1⟩,⟨1,−2⟩}. B={⟨1,2⟩,⟨3,5⟩},C={⟨−1,1⟩,⟨1,−2⟩}. Find th
Tamiku [17]
Answer:
This question is maybe r2+ =>()0?
Step-by-step explanation:
sub 2 for any "x"
3(2)^2-2(2)+1
6^2-4+1 i dont know if you need to simplify even more but if you do
36-4+1 32+1 31
i hope this helps you!
Answer:
2:1____________________________________
