The perimeter of the triangle is 40 units
<h3>Perimeter of a triangle</h3>
From the question, we are to determine the perimeter of the given triangle
From the given diagram, we can observe that the triangle is a right triangle
The vertical length of the triangle is 15 units
and the horizontal length of the triangle is 8 units
Thus,
We can find the hypotenuse by using the<em> Pythagorean theorem </em>
Let the hypotenuse be h
Then,
h² = 15² + 8²
h² = 225 + 64
h² = 289
h = √289
h = 17 units
Now, for the perimeter of the triangle
The perimeter of a triangle is the sum of all its three sides
Thus,
The perimeter. P, of the triangle is
P = 15 + 8 + 17
P = 40 units
Hence, the perimeter of the triangle is 40 units
Learn more on Calculating perimeter here: brainly.com/question/17394545
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Answer:
(x, y) = (2, 1)
Step-by-step explanation:
Adding the two equations gives ...
2y = 2
y = 1 . . . . . divide by 2
Subtracting the second equation from the first gives ...
0 = 6x -12
0 = x -2 . . . . divide by 6
2 = x
The solution is (x, y) = (2, 1).
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The attached graph verifies this solution.
Answer:
-1/7
Step-by-step explanation:
Divide the first expression by the second expression.
Answer: Choice A, f ' (c) = 3
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Work Shown:
f(-1) = -3 means the point (-1,-3) is on the f(x) curve.
f(4) = 12 means (4,12) is on the f(x) curve as well.
Compute the slope of the line through those two points.
Slope formula
m = (y2 - y1)/(x2 - x1)
m = (12 - (-3))/(4 - (-1))
m = (12+3)/(4+1)
m = 15/5
m = 3
The slope of the secant line through (-1,-3) and (4,12) is m = 3
Through the mean value theorem (MVT), there exists at least one value c such that f ' (c) = 3, where -1 < c < 4, and f(x) is a continuous and differentiable function on this interval in question.
Visually, there exists at least one tangent line that has the same slope of the secant line mentioned. Lines with equal slopes, and different y intercepts, are parallel.
