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blondinia [14]
3 years ago
15

If 20 is decreased to 18.6, the decrease is what percent of the original number?

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

1.4

Step-by-step explanation:

10 decreased by 1.4 is 18.6

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2nd opinion that’s your answer
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Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
3 years ago
David is buying fish for his aquarium. Clown fish cost $12 each and angel fish cost $7 each. If he has $100 to spend, and he wan
Anni [7]

Answer:

6 clown fish and 4 angel fish

Step-by-step explanation:

<u>lets say he bought 8 clown fish. </u>

12*8 = 96

the last 4 dollars wont be used.

<u>lets say he bought 7 clown fish-</u>

12*7 = 84

100 - 84 = 16. 16 is not a multiple of 7.

<u>lets say he bought 6 clown fish,</u>

12*6 = 72

100 - 72 = 28

28/7 = 4

If David has $100 dollars to spend and wants to spend every dollar, he can buy 6 clown fish and 4 angel fish.

3 0
2 years ago
Factor the expression.
nalin [4]
6x^2+14x+4
First factor out all numerical factors (=2 in this case)
2(3x^2+7x+2)
look for m,n such that m*n=3*2, m+n=7 => m=6, n=1
2(3x^2+6x  + 1x+2)
Factor 3x^2+6x into 3x(x+2)
2( 3x(x+2)+1(x+2) )
factor out common factor (x+2)
2(x+2)(3x+1)
=>
6x^2+14x+4=2(x+2)(3x+1)
8 0
3 years ago
Please answer this correctly without making mistakes
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Answer:

2+3s

Step-by-step explanation:

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