Answer:
a)The approximate radius of the nucleus of this atom is 4.656 fermi.
b) The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527
Explanation:
![r=r_o\times A^{\frac{1}{3}}](https://tex.z-dn.net/?f=r%3Dr_o%5Ctimes%20A%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
= Constant for all nuclei
r = Radius of the nucleus
A = Number of nucleons
a) Given atomic number of an element = 25
Atomic mass or nucleon number = 52
![r=1.25 \times 10^{-15} m\times (52)^{\frac{1}{3}}](https://tex.z-dn.net/?f=r%3D1.25%20%5Ctimes%2010%5E%7B-15%7D%20m%5Ctimes%20%2852%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![r=4.6656\times 10^{-15} m=4.6656 fm](https://tex.z-dn.net/?f=r%3D4.6656%5Ctimes%2010%5E%7B-15%7D%20m%3D4.6656%20fm)
The approximate radius of the nucleus of this atom is 4.656 fermi.
b) ![F=k\times \frac{q_1q_2}{a^2}](https://tex.z-dn.net/?f=F%3Dk%5Ctimes%20%5Cfrac%7Bq_1q_2%7D%7Ba%5E2%7D)
k=
= Coulombs constant
= charges kept at distance 'a' from each other
F = electrostatic force between charges
![q_1=+1.602\times 10^{-19} C](https://tex.z-dn.net/?f=q_1%3D%2B1.602%5Ctimes%2010%5E%7B-19%7D%20C)
![q_2=+1.602\times 10^{-19} C](https://tex.z-dn.net/?f=q_2%3D%2B1.602%5Ctimes%2010%5E%7B-19%7D%20C)
Force of repulsion between two protons on opposite sides of the diameter
![a=2\times r=2\times 4.6656\times 10^{-15} m=9.3312\times 10^{-15} m](https://tex.z-dn.net/?f=a%3D2%5Ctimes%20r%3D2%5Ctimes%204.6656%5Ctimes%2010%5E%7B-15%7D%20m%3D9.3312%5Ctimes%2010%5E%7B-15%7D%20m)
![F=9\times 10^9 N m^2/C^2\times \frac{(+1.602\times 10^{-19} C)\times (+1.602\times 10^{-19} C)}{(9.3312\times 10^{-15} m)^2}](https://tex.z-dn.net/?f=F%3D9%5Ctimes%2010%5E9%20N%20m%5E2%2FC%5E2%5Ctimes%20%5Cfrac%7B%28%2B1.602%5Ctimes%2010%5E%7B-19%7D%20C%29%5Ctimes%20%28%2B1.602%5Ctimes%2010%5E%7B-19%7D%20C%29%7D%7B%289.3312%5Ctimes%2010%5E%7B-15%7D%20m%29%5E2%7D)
![F=2.6527 N](https://tex.z-dn.net/?f=F%3D2.6527%20N)
The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527
Answer: Both forces are equal each other.
Explanation:
If we assume that no external forces act during the collision (based on the fact that the collision time is very small), total momentum must be conserved, and Newton's 3rd law must apply.
If the total momentum is conserved, the change in momentum for the automobile (caused by the truck) must be equal to the one caused to the truck by the car.
This change in momentum is caused by internal forces, which must be equal each other (even though of opposite signs).
Another way to explain this, is that by Newton's 3rd Law, the force applied by the automobile to the car, must be equal and opposite to the one the truck is applying to the car at the same time.
Answer:
0.4
Explanation:
Given that a particular inductor is connected to a circuit where it experiences a change in current of 0.8 amps every 0.10 sec. If the inductor has a self-inductance of 2.0 V, what is the inductance
Using the power formula
P = IV
Substitute all the parameters
P = 0.8 × 2
P = 1.6 W
But P = I^2 R
Substitute power and current
1.6 = 0.8^2 R
R = 1.6 / 0.64
R = 2.5 ohms
Inductance = reciprocal of resistance
Inductance = 1 / 2.5
Inductance = 0.4
Answer:
Explanation:
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