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laila [671]
3 years ago
13

When the Voyager I and Voyager II spacecraft were exploring the outer planets, NASA flight controllers had to plan the crafts' m

oves well in advance. How many seconds elapse between the time a command is sent from Earth and the time the command is received by Voyager at Neptune? Assume the distance from Earth to Neptune is 4.76E+12 m.
Physics
1 answer:
ella [17]3 years ago
5 0

Answer:

1.59*10^4 s

Explanation:

The signals sent from the earth, travel at the speed of light, therefore the travel time of the signal between the earth and neptune, can be calculated with the following equation, which relates time, speed and distance:

t=\frac{x}{v}\\t=\frac{4.76*10^{12} m}{3*10^8 m/s}=1.59*10^4 s\\

The time elapsed is approximately 4.41 hours

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JulijaS [17]
The ball drops about 1 m.

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What is the bending of a wave around a barrier?
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That's wave 'diffraction'.
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You have a pulley 10.4 cm in diameter and with a mass of 2.3 kg. You get to wondering whether the pulley is uniform. That is, is
madreJ [45]

Answer:

Explanation:

Given

Diameter of Pulley=10.4 cm

mass of Pulley(m)=2.3 kg

mass of book(m_0)=1.7 kg

height(h)=1 m

time taken=0.64 s

h=ut+frac{at^2}{2}

1=0+\frac{a(0.64)^2}{2}

a=4.88 m/s^2and [tex]a=\alpha r

where \alphais angular acceleration of pulley

4.88=\alpha \times 5.2\times 10^{-2}

\alpha =93.84 rad/s^2

And Tension in Rope

T=m(g-a)

T=1.7\times (9.8-4.88)

T=8.364 N

and Tension will provide Torque

T\times r=I\cdot \alpha

8.364\times 5.2\times 10^{-2}=I\times 93.84

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4 0
3 years ago
A baseball hit just above the ground leaves the bat 27 m/s at 45° above the horizontal. A) How far away does the ball strike the
Sedbober [7]

Answer:

A) The ball hits the ground 74.45 m far from the hitting position.

B) Maximum height of the ball = 18.57 m

Explanation:

There are two types of motion in this horizontal and vertical motion.

We have velocity = 27 m/s at 45° above the horizontal

Horizontal velocity = 27cos45 = 19.09 m/s

Vertical velocity = 27sin45 = 19.09 m/s

Time to reach maximum height,

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     Horizontal distance traveled = 19.09 x 3.90 = 74.45 m

     So the ball hits the ground 74.45 m far from the hitting position.

B) We have vertical displacement

              S = ut + 0.5 at²

              H = 19.09 x 1.95 - 0.5 x 9.81 x 1.95² = 18.57 m

    Maximum height of the ball = 18.57 m

6 0
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What is the build up of electrons on a surface
Minchanka [31]

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Static energy

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