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laila [671]
3 years ago
13

When the Voyager I and Voyager II spacecraft were exploring the outer planets, NASA flight controllers had to plan the crafts' m

oves well in advance. How many seconds elapse between the time a command is sent from Earth and the time the command is received by Voyager at Neptune? Assume the distance from Earth to Neptune is 4.76E+12 m.
Physics
1 answer:
ella [17]3 years ago
5 0

Answer:

1.59*10^4 s

Explanation:

The signals sent from the earth, travel at the speed of light, therefore the travel time of the signal between the earth and neptune, can be calculated with the following equation, which relates time, speed and distance:

t=\frac{x}{v}\\t=\frac{4.76*10^{12} m}{3*10^8 m/s}=1.59*10^4 s\\

The time elapsed is approximately 4.41 hours

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blsea [12.9K]

Answer:

The temperature is 2541.799 K

Explanation:

The formula for black body radiation is given by the relation;

Q = eσAT⁴

Where:

Q = Rate of heat transfer 56.6

σ = Stefan-Boltzman constant = 5.67 × 10⁻⁸ W/(m²·k⁴)

A = Surface area of the cube = 6×(3.72 mm)² = 8.3 × 10⁻⁵ m²

e = emissivity = 0.288

T = Temperature

Therefore, we have;

T⁴ = Q/(e×σ×A) = 56.6/(5.67 × 10⁻⁸ × 8.3 × 10⁻⁵ × 0.288) = 4.174 × 10¹⁴ K⁴

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Power is the rate which work is done.

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