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marusya05 [52]
3 years ago
15

A stack of 200 pennies is 1.325 inches tall. Mario guesses that each penny is 0.013 inches thick. Explain how you know Mario’s a

nswer is not correct.
Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0

Answer:

200 divided by 1.325 = 0.006625 thats how big each penny is hope this helped! :)

Step-by-step explanation:

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Disclaimer: Exchange rates vary almost on a constant basis, so it is best to always have an up-to-date chart from an online source. For the purposes of this problem, we don't have to worry about the rates changing.

------------------

25 U.S Dollars = 20 Euros

25/20 U.S. Dollars = 20/20 Euros

1.25 U.S. Dollars = 1 Euro

<h3>The exchange rate is 1.25 U.S. Dollars per Euro</h3>

Saying "per Euro" is the same as saying "per 1 Euro". I divided both sides of the second equation by 20 so that I could turn the "20 Euros" into "1 Euro".

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Answer:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

Step-by-step explanation:

Information given

\bar X=8.19 cm^3 represent the sample mean

s=0.8 cm^3 represent the sample deviation

n=17 sample size  

\mu_o =9.02 represent the value to verify

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value

System of hypothesis to check

We want to check if the true mean is less than the normal value of 9.02 cm^3, the system of hypothesis would be:  

Null hypothesis:\mu \geq 9.02  

Alternative hypothesis:\mu < 9.02  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28    

The degrees of freedom are given by

df=n-1=17-1=16  

The p value would be given by this probability:

p_v =P(t_{(16)}  

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

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