Coordinates of the vertices of JKL
J = (-5,-2)
K = (-3, -6)
L = (-1, -6)
Translation two units left => new x-coordinate = original x-coordinate - 2 and y-coordinate does not change.
J' = (-7,-2)
k' = (-5,-6)
L' = (-3,-6)
6x^3 a negative times a negative cancels out making it positive
Step-by-step explanation:
5x - 7 = 13
5x = 13 + 7
5x = 20
x = 20 ÷ 4 = 5
10x - 14
10(5) - 14 = 50 - 14 = 36
Answer:
<h3>The lecturer has to divide the class into 3 groups of 6
which have 1 girl in each group to have 1 girl in each class.</h3>
(sry if this sounds a little akward didn't have enough time to type this answer out).
