Question

A chemist places a 100 g cube of each of the metals listed in the table on a separate hot plate. Based on the specific heat values in the table, rank the metals in terms of how quickly they will reach the target temperature of 80°c. Use "1" to indicate the fastest and "5" to indicate the slowest. Fe: al: cu: sn: pb:.

Answer 1

The ranking of the metals in terms of how quickly they reach the target temperature are; Pb: 1, Sn: 2, Cu: 3, Fe: 4, Al: 5

Solving Specific Heat Capacity

The formula for quantity of heat from specific heat capacity is;

Q = m * C_s * ΔT

where;

Q is specific heat energy

C_s is specific heat capacity

ΔT is change in temperature

m is mass

Thus, the lower the specific heat or quantity of heat energy, the faster the change in temperature

Making ΔT the subject of the formula gives;

ΔT = Q / ( m * Cs)

We are told that the heat (Q) and mass (m = 100 g) are equal for the five samples. Thus, we have;

ΔT = [Q/m]/C_s

Since Q/m is constant for all the 5 samples, inputting the specific heat capacities means that the higher the specific heat capacity the slower the change in temperature but the lower the specific heat capacity, the quicker the change in temperature.

Solving online means that the fastest to slowest are;

Pb: 1, Sn: 2, Cu: 3, Fe: 4, Al: 5

Read more about Specific Heat energy at; brainly.com/question/13439286