Answer:
there are 4725 different ways to pick the 11 players
Step-by-step explanation:
assuming that a player can only play from its position and not from the other 2 , then each defensive position is independent from the others , and since the order each player is chosen is not relevant we have that:
total combinations = possible combinations of linemen * possible combinations of linebackers * possible combinations of defensive backs = combinations of 5 linemen from 7 * combinations of 4 linebackers from 6 * combinations of 2 defensive backs from 6 = [ 7!/(5!*(7-5)!] * [ 6!/(4!*(6-4)!] * [ 6!/(2!*(6-2)!] = 7!/(2!*5!)*[ 6!/(4!*2!)]² = 4725 combinations
thus there are 4725 different ways to pick the 11 players
Answer:
I think the answer is 100%
Every year the day of the same date is different so let’s say my birthday this year is Thursday next year it will be Friday so 25-16 = 9 years so friday + 9 days = Sunday
Hope it helps!
Can I get brainliest
<span>All types of conic sections, arranged with increasing eccentricity. Note that curvature decreases with eccentricity, and that none of these curves intersect.</span>
The volume of any cube is
V = s3
where:
V = volume
s = side
Your side is given. Therefore, the volume is
V = (5a + 4b)3
V = (5a + 4b)(5a + 4b)(5a + 4b)
V = (25a2 + 40ab + 16b2)(5a + 4b)
V = 5a(25a2 + 40ab + 16b2) + 4b(25a2 + 40ab + 16b2)
V = 125a3 + 200a2b + 80ab2 + 100a2b + 160ab2 + 64b3
V = 125a3 + 300a2b + 240ab2 + 64b3