Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.
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- The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
- <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.
To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:
27 - 18 - 30|3
9 - 6 - 10
No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.
A similar problem is given at brainly.com/question/6032811
Firstly, $3.99 × 5 = $19.95
Second, $2.75 × 5 = $13.75
Third, $2.70 × 3 = $8.1 (Since it is just $8.1 that won't make sense so we'd add a 0 so It's $8.10.)
Then we do the last one which is 13 × $0.89 = $11.57.
So now since we are done multiplying we can add it all up.
The answer is $53.37 when we finish adding it up.
and I don't know what A number sentence is sorry :(
I took a long time typing this :< I hope this helps though! :D
Answer:
75.52
Step-by-step explanation:
All you have to do is second cos, or cos^-1(2/8), because of sohcahtoa, adjacent hypotenuse, so it is cos.