Answer:
The probability that at most 1 car will require major engine repair next year is P=0.3392.
Step-by-step explanation:
This can be modeled as a binomial random variable, with n=22 and p=0.1.
The probability that exavtly k cars will require major engine repair next year is:

Then, the probability that at most 1 car will require major engine repair next year is:

Answer: Isolate the variable by dividing each side by factors that don't contain the variable.
k = −1
They would mostly be interested in accounting
240 is 240% of 576
240% x 240 = x
(240 x 240) divide by 100
57,600 divide by 100 = 576
x = 576