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alexdok [17]
2 years ago
6

Can you solve this question? I would help a lot remember to explain it :)

Mathematics
2 answers:
KengaRu [80]2 years ago
8 0
Each E Tank has a value of 1.5
Natasha2012 [34]2 years ago
7 0
Each E tank has a value of 1.5

Using the subtraction property of equality, we can subtract two of the yellow things from each side of the equation. After that, we’re left with three yellow things on the right and two E tanks on the left. After dividing both by two, we get that one E tank is equivalent to one and a half yellow things
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Plsss helppp, tysmm!!
Vinvika [58]

Answer:

It should be PT and NO

Hope this helps!

4 0
3 years ago
Tom's coach keeps track of the number of plays that Tom carries the ball and how many yards he gains. Select all the statements
Brums [2.3K]

Answer:The dependent variable is the number of plays he carries the ball.

The independent variable is the number of touchdowns he scores.

The dependent variable is the number of yards he gains.

These are the ones that you need to choose.

7 0
3 years ago
Write 2.14 x 10-6 in standard form.
Nadusha1986 [10]

Answer:

0.00000214

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Nate rented a power washer and a generator. On his first job, he used each piece of equipment for 6 hours which cost $90. On his
sp2606 [1]

Answer:

Step-by-step explanation:

p = power washer and g = generator

6p + 6g = 90 .....multiply by 4

4p + 8g = 100 ....multiply by -6

---------------------

24p + 24g = 360 (result of multiplying by 4)

-24p - 48g = -600 (result of multiplying by -6)

---------------------add

-24g = - 240

g = -240 / -24

g = 10 <=== the generator cost $ 10 per hr

6p + 6g = 90

6p + 6(10) = 90

6p + 60 = 90

6p = 90 - 60

6p = 30

p = 30/6

p = 5 <==== the power washer costs $ 5 per hr

check...

4p + 8g = 100

4(5) + 8(10) = 100

20 + 80 = 100

100 = 100 (correct)

3 0
3 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
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