Question

The school designed their garden to have a perimeter of 32 ft with the length measuring two feet more than twice the width

Answer 1

Based on the perimeter solved, the length and width of the rectangle will be 11.34 feet and 4.67 feet respectively.

How to solve the perimeter

Width = w

Length = 2w + 2

Perimeter = 2(Length + Width)

Perimeter = 2(Length + Width)

32 = 2(2w + 2 + w)

32 = 4w + 4 + 2w

32 - 4 = 6w

28 = 6w

w = 28/6 = 4.67

Length = 2w + 2 = (2 × 4.67) + 2 = 11.34

Learn more about perimeter on:

brainly.com/question/19819849