The school designed their garden to have a perimeter of 32 ft with the length measuring two feet more than twice the width
1 answer:
Based on the perimeter solved, the length and width of the rectangle will be 11.34 feet and 4.67 feet respectively.
<h3>How to solve the perimeter</h3>
Width = w
Length = 2w + 2
Perimeter = 2(Length + Width)
Perimeter = 2(Length + Width)
32 = 2(2w + 2 + w)
32 = 4w + 4 + 2w
32 - 4 = 6w
28 = 6w
w = 28/6 = 4.67
Length = 2w + 2 = (2 × 4.67) + 2 = 11.34
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