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kherson [118]
3 years ago
14

Pls help have to turn in in like 5 minutes ​

Mathematics
2 answers:
sammy [17]3 years ago
8 0

Answer:

Second option is the correct choice.

Step-by-step explanation:

Perimeter = 13a + 7b + 4.5c

Regards: Umer

olchik [2.2K]3 years ago
3 0

Answer:

B. 13a + 7b + 4.5c

Step-by-step explanation:

trust me bruh

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Write the equation of a line that contains (2,−2) and perpendicular to another line with slope −1. (20 POINTS)
Kay [80]
Y=mx+b or -2=-1 x 2+b, b= -2(-1)(2) b=0

Therefore the equation of the line is

y=-1x
8 0
3 years ago
Use completing the aquare to solve for x in the equation (x+7)(x-9)=25​
Tema [17]

Answer:

x = 1 + sqrt(89) or x = 1 - sqrt(89)

Step-by-step explanation:

Solve for x:

(x - 9) (x + 7) = 25

Expand out terms of the left hand side:

x^2 - 2 x - 63 = 25

Add 63 to both sides:

x^2 - 2 x = 88

Add 1 to both sides:

x^2 - 2 x + 1 = 89

Write the left hand side as a square:

(x - 1)^2 = 89

Take the square root of both sides:

x - 1 = sqrt(89) or x - 1 = -sqrt(89)

Add 1 to both sides:

x = 1 + sqrt(89) or x - 1 = -sqrt(89)

Add 1 to both sides:

Answer: x = 1 + sqrt(89) or x = 1 - sqrt(89)

7 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Ipatiy [6.2K]

Answer:

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

Step-by-step explanation:

2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c =  - 3 \\\\x = \frac{-b^2\  \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

3 0
3 years ago
4 ( x- 2) = 34 for x
DerKrebs [107]
X=21/2
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X=10.5
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