45 square feet is the area of the base of the pedestal.
what is rectangular prism?
- A rectangular prism is a 3D figure with 6 rectangular faces.
- To find the volume of a rectangular prism, multiply its 3 dimensions: length x width x height. The volume is expressed in cubic units.
we know that
The volume of the pedestal (rectangular prism) is given by the formula
V = B × h
where
B is the area of the rectangular base of pedestal
V = 405 ft³
h = 9 ft
put the given values in the formula and solve for B
405 = B × 9
B = 405/9
B = 45 ft²
Therefore, 45 square feet is the area of the base of the pedestal.
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X+6 is the correct answer
Step-by-step explanation:
this is the answer I wish it willhelp
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Use the attached figure to guide yourself through the explanation. In the figure:

.
We know that:

Also remmeber that the area of a triangle is:

The hegiht is shown in the figure in red, the base is just the b side.
Using the angle C the area of the triangle is:

Now taking the derivative of the area 2A with respect to t we have:

Replacing with the right values:

yields: