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mixas84 [53]
3 years ago
7

Describe the transformation from the graph of f(x) = x + 3 to the graph of g(x) = x − 2

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

C. The graph g(x) = x − 7 is the result of translating the graph of f(x) = x + 3 down 10 units.

Sure hope this helps you and good on whatever math test or exam is coming up soon!! :D

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If (x+2) is a factor of x^3-6x^2+kx+10, k=
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If a binomial (x-a) is a factor of a polynomial, then a is a root of this polynomial.

(x+2)=(x-(-2)) \Rightarrow a=-2\\\\
(-2)^3-6\cdot(-2)^2+k\cdot(-2)+10=0\\
-8-24-2k+10=0\\
-2k=22\\\
\boxed{k=-11}


3 0
3 years ago
The sum of 15 and the product of 5 and v
pogonyaev
The answer is 3 because 3×5=15
7 0
3 years ago
700 divided by 12 <br> Please help me
kogti [31]
700/12 equals 58 and 1/3.
6 0
3 years ago
Read 2 more answers
Subtract 6 from me. Then multiply by 2. If you subtract 40 and then divide by 4, you get 8. What number am I?
aliina [53]

Answer:

42

Step-by-step explanation:

Let the number be "x"

We translate the word equation to algebraic equation.

First,

subtract 6 from me, so we have:

x - 6

Now,

Multiply by 2, so we have:

2(x-6)

Now,

Subtract 40, then divide by 4:

\frac{2(x-6)-40}{4}

Now, you get "8", so equate this to 8, we get:

\frac{2(x-6)-40}{4}=8

We now solve using algebra:

\frac{2(x-6)-40}{4}=8\\2(x-6)-40=4*8\\2(x-6)-40=32\\2x-12-40=32\\2x-52=32\\2x=32+52\\2x=84\\x=42

The number is 42

7 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
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