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sergey [27]
3 years ago
7

5

e" class="latex-formula"> + -\frac{1}{4}
-\frac{2}{3} + \frac{1}{6}
-\frac{8}{5} + -\frac{3}{4}

please help me!! <3
Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

<u>Solution for Part-a</u>

  • 5 3/4 + (1/-4)
  • => {(5 x 4) + 3}/4 + (-1/4)
  • => {20 + 3}/4 - 1/4
  • => 23/4 - 1/4
  • => 22/4 = 11/2 = 5.5

<u>Solution for Part-b</u>

  • (2/-3) + 1/6
  • => -2/3 + 1/6
  • => -4/6 + 1/6
  • => -3/6 = -0.5

<u>Solution for Part-c</u>

  • (8/-5) + (3/-4)
  • => -8/5 - 3/4
  • => -32/20 - 15/20
  • => -47/20 = -2.35

Hoped this helped!

meriva3 years ago
7 0
These are the answers for your problem

1. 11/2

2. -1/2

3. -17/20
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Step-by-step explanation:

Step 1:

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rotation of 90 degrees counterclockwise about the origin, point O, then a reflection across the x-axis reflection across the y-a
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Answer:

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(x,y) = (-y,x)

(-x,y)=(-y,-x)

(-x,-y)=(y,-x)

(x,-y) =(y,x)

Then Reflection across X axis has taken place.

(-y,x) = (-y,-x)

(-y,-x)=(-y,x)

(y,-x)=(y,x)

(y,x)=(y,-x)

Then a reflection across the y-axis has taken place.

(-y,-x)=(y,-x)

(-y,x) = (y,x)

(y,x) =(-y,x)

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Then a translation a units to the right and b units up has taken place.

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[-(-y+a),-(x+b)]=[(-y+a),-(x+b)]

[-(-y+a),-(-x+b)]=[(-y+a),-(-x+b)]

Totally depends on value of a and b on which quadrant these point lies.



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