Are the following pairs of structures resonance contributors or different compounds?.

1 answer:

8 0

Answer:Determine whether the following pairs of structures are actually different compounds or simply resonance forms of the same

Explanation:

12pm MWF SEC 100 Professor Thomas Teets Units and Significant Figures 01-20-2016 Units: required to make a measurement have meaning; ALL MEASURED QUANTITES NEED UNITS SI Units to Know: Mass Kilogram (kg) Length Meter (m) Time Seconds (s) Temperature Kelvin (K) *NO degree symbol* Amount of substance Mole (mol) Prefixes to Know: Table R-2 in Textbook When these prefixes are added to units, it changes the size of that unit by the given amount (in multiples of 10 ) Mega (M)

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The following data is collected after eluting a TLC plate containing three sample spots (A, B, and C): distance traveled by comp

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Answer:

Rf = 0.26

Explanation:

The Rf value is calculated by dividing the distance traveled by a compound, by the distance traveled by the solvent front. In other words, the length of the TLC plate is not relevant in calculating a Rf value.

Distance traveled by compound C = 18 mm

Distance traveled by the solvent front = 70 mm

Rf = 18/70 = 0.26

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Answer: Energy = 10000J - 2000J = 8000J

Therefore, the energy is dissipated the skier moves down to the slope is 8000J

Explanation:

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Hydrogen and nitrogen react to form ammonia according to the reaction,

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your answer would be 2.0

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Please help!-- 20 pts!

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Answer: The positively charged ions will be attracted to the negative electrode and gain electrons. Meanwhile, the negatively charged ions will be attracted to the positive electrode and release electrons.

Explanation:

Electrolysis is breaking down of a substance into its constituents by the action of electrical current.

$LiCl\rightarrow Li^++Cl^-$

Cations wich are positively charged specie moves towards the negatively charged electrode that is towards the cathode. On reaching cathode, cations accepts electrons and get reduced through reduction reaction.

$Li^++e^-\rightarrow Li$

Anions wich are negatively charged specie moves towards the positively charged electrode that is towards the anode. On reaching anode, anions donate electrons and get oxidized through oxidation reaction.

$Cl^-\rightarrow Cl+e^-$