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BlackZzzverrR [31]
2 years ago
13

Three people bought copper items, and they each relied on different properties of copper. Bernie bought a set of dishes that inc

luded a copper salad bowl. Nicholas went to the hardware store and bought 12-gauge wire. Matt bought his mother a copper bracelet.
Which property most likely attracted each buyer to his item?

Bernie relied on conductivity, Nicholas relied on ductility, and Matt relied on malleability.
Bernie relied on ductility, Nicholas relied on malleability, and Matt relied on appearance.
Bernie relied on malleability, Nicholas relied on ductility, and Matt relied on appearance.
Bernie relied on malleability, Nicholas relied on appearance, and Matt relied on conductivity.
Chemistry
1 answer:
jasenka [17]2 years ago
8 0

Answer:

C.) Bernie relied on malleability, Nicholas relied on ductility, and Matt relied on appearance.

Explanation:

I took the quiz on edge

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The symbols from the list and match them with the names of the
stich3 [128]
Be - Beryllium
S - sulfur
K - Potassium
C - Carbon
B - Boron
Ar - Argon
O - oxygen
Ne - Neon
Ca - Calcium
H - Hydrogen
3 0
2 years ago
Why were scientists unsure about the last common ancestor between apes and humans?
nadezda [96]

Answer:

Scientists were unsure about the last common ancestor between apes and humans because fossils are so scarce, researchers do not know what the last common ancestors of living apes and humans looked like or where they originated.

Explanation:

7 0
2 years ago
A sample of argon gas has a volume of 73 mL at a pressure of 1.20 atm and a temperature of 112 degrees Celsius. What is the fina
NeX [460]

Answer:

V₂ → 106.6 mL

Explanation:

We apply the Ideal Gases Law to solve the problem. For the two situations:

P . V = n . R . T

Moles are still the same so → P. V / R. T = n

As R is a constant, the formula to solve this is: P . V / T

P₁ . V₁ / T₁ = P₂ .V₂ / T₂   Let's replace data:

(1.20 atm . 73mL) / 112°C = (0.55 atm . V₂) / 75°C

((87.6 mL.atm) / 112°C) . 75°C = 0.55 atm . V₂

58.66 mL.atm = 0.55 atm . V₂

58.66 mL.atm / 0.55 atm = V₂ → 106.6 mL

3 0
3 years ago
Use the ideal gas law to calculate the concentrations of nitrogen and oxygen present in air at a pressure of 1.0 atm and a tempe
notka56 [123]

Answer:

[N₂] = 0.032 M

[O₂] = 0.0086 M

Explanation:

Ideal Gas Law → P . V = n .  R . T

We assume that the mixture of air occupies a volume of 1 L

78% N₂ → Mole fraction of N₂ = 0.78

21% O₂  → Mole fraction of O₂ = 0.21

1% another gases  → Mole fraction of another gases = 0.01

In a mixture, the total pressure of the system refers to total moles of the mixture

1 atm . 1L = n . 0.082L.atm/mol.K . 298K

n = 1 L.atm / 0.082L.atm/mol.K . 298K → 0.0409 moles

We apply the mole fraction to determine the moles

N₂ moles / Total moles = 0.78 → 0.78 . 0.0409 mol = 0.032 moles N₂

O₂ moles / Total moles = 0.21 → 0.21 . 0.0409 mol = 0.0086 moles O₂

4 0
3 years ago
What is the total number of moles of oxygen atoms in 1 mole of N2O3
Rama09 [41]
N₂O₃

3 moles oxgyen atoms in 1 mole .

hope this helps!


7 0
2 years ago
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