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2 years ago

Please help!-- 20 pts!

2 answers:

5 0

Answer: The positively charged ions will be attracted to the negative electrode and gain electrons. Meanwhile, the negatively charged ions will be attracted to the positive electrode and release electrons.

Explanation:

Electrolysis is breaking down of a substance into its constituents by the action of electrical current.

$LiCl\rightarrow Li^++Cl^-$

Cations wich are positively charged specie moves towards the negatively charged electrode that is towards the cathode. On reaching cathode, cations accepts electrons and get reduced through reduction reaction.

$Li^++e^-\rightarrow Li$

Anions wich are negatively charged specie moves towards the positively charged electrode that is towards the anode. On reaching anode, anions donate electrons and get oxidized through oxidation reaction.

$Cl^-\rightarrow Cl+e^-$

DochEvi [55]2 years ago

5 0

Answer:

The positively charged ions will be attracted to the negative electrode and gain electrons. Meanwhile, the negatively charged ions will be attracted to the positive electrode and release electrons.

Explanation:

I just had this question and got it right

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Difference between hygroscopic and deliquescent substance with of each

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Answer:

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3 years ago

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Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT

marysya [2.9K]

Answer:

(a) The length at temperature 180°C is 40.070 cm

(b) The length at temperature 90°C is 64.976 inches

Explanation:

(a) The given parameters are

The thermal expansion coefficient, α for steel = 1.24 × 10⁻⁵/°C

The initial length of the steel L₀ = 40 cm

The initial temperature, t₀ = 40°C

The length at temperature 180°C = L

Therefore, from the given relation, for change in length, ΔL, we have;

ΔL = α × L₀ × ΔT

The amount the temperature changed ΔT = 180°C - 40°C = 140°C

Therefore, the change in length, ΔL, is found as follows;

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 40 × 140°C = 0.07 cm

Therefore, L = L₀ + ΔL = 40 + 0.07 = 40.07 cm

The length at temperature 180°C = 40.07 cm

(b) Given that the length at T = 120°C is 65 in., we have;

The temperature at which the new length is sought = 90°C

The amount the temperature changed ΔT = 90°C - 120°C = -30°C

ΔL = α × L₀ × ΔT = 1.24 × 10⁻⁵/°C × 65 × -30°C = -0.024375 inches

The length, L at 90°C is therefore, L = L₀ + ΔL = 65 - 0.024375 = 64.976 in.

The length at temperature 90°C = 64.976 inches

Therefore;

L = 60 + α × 60 × (T - 150°C)

L = 60 + α × 60 × T - 9000 × α

L(T, α) = 60·α·T - 9000·α + 60

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