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2 years ago

Please help!-- 20 pts!

2 answers:

5 0

Answer: The positively charged ions will be attracted to the negative electrode and gain electrons. Meanwhile, the negatively charged ions will be attracted to the positive electrode and release electrons.

Explanation:

Electrolysis is breaking down of a substance into its constituents by the action of electrical current.

$LiCl\rightarrow Li^++Cl^-$

Cations wich are positively charged specie moves towards the negatively charged electrode that is towards the cathode. On reaching cathode, cations accepts electrons and get reduced through reduction reaction.

$Li^++e^-\rightarrow Li$

Anions wich are negatively charged specie moves towards the positively charged electrode that is towards the anode. On reaching anode, anions donate electrons and get oxidized through oxidation reaction.

$Cl^-\rightarrow Cl+e^-$

DochEvi [55]2 years ago

5 0

Answer:

The positively charged ions will be attracted to the negative electrode and gain electrons. Meanwhile, the negatively charged ions will be attracted to the positive electrode and release electrons.

Explanation:

I just had this question and got it right

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ludmilkaskok [199]

Answer:

$\large \boxed{\text{5.9 s}}$

Explanation:

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Data:

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Calculation

$\begin{array}{rcl}\dfrac{t_{2}}{t_{1}} & = & \sqrt{\dfrac{M_{2}}{M_{1}}}\\\\\dfrac{t_{2}}{\text{5 s}}& = & \sqrt{\dfrac{44.01}{32.00}}\\\\& = & \sqrt{1.375}\\t_{2}& = & \text{5 s}\times 1.173\\& = & \mathbf{5.9 s} \\\end{array}\\\text{It will take $\large \boxed{\textbf{5.9 s}}$ for the carbon dioxide to effuse.}$

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