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enot [183]
2 years ago
12

Use percents to compare attendance at two concerts: 299 people attended the first concert, while 949 attended the second. pls he

lpppp
Mathematics
1 answer:
Lisa [10]2 years ago
8 0

At the second concert, there were 217% more people than in the first concert.

<h3>What are percentages?</h3>

Percentage can be described as a fraction out of an amount that is usually expressed as a number out of hundred. The sign used to represent percentages is %.

<h3>What is the comparison between the two concerts?</h3>

Number of people who attended the second concert compared to the first concert = (949/299) - 1 x 100 = 217%

To learn more about percentages, please check: brainly.com/question/25764815

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A national college researcher reported that 65% of students who graduated from high school in 2012 enrolled in college. Twenty n
Usimov [2.4K]

Answer:

a) The probability that exactly 17 of them enroll in college is 0.116.

b) The probability that more than 14 enroll in college is 0.995.

c) The probability that fewer than 11 enroll in college is 0.001.

d) It would be be unusual if more than 24 of them enroll in college since the probability is 0.009.

Step-by-step explanation:

We can model this with a binomial distribution, with n=29 and p=0.65.

The probability that k students from the sample who graduated from high school in 2012 enrolled in college is:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{29}{k} 0.65^{k} 0.35^{29-k}\\\\\\

a) The probability that exactly 17 of them enroll in college is:

P(x=17) = \dbinom{29}{17} p^{17}(1-p)^{12}=51895935*0.0007*0=0.116\\\\\\

b) The probability that more than 14 of them enroll in college is:

P(X>14)=\sum_{15}^{29} P(X=k_i)=1-\sum_{0}^{14} P(X=k_i)\\\\\\P(x=0)=0\\\\P(x=1)=0\\\\P(x=2)=0\\\\P(x=3)=0\\\\P(x=4)=0\\\\P(x=5)=0\\\\P(x=6)=0\\\\P(x=7)=0\\\\P(x=8)=0\\\\P(x=9)=0\\\\P(x=10)=0.001\\\\P(x=11)=0.002\\\\P(x=12)=0.005\\\\P(x=13)=0.013\\\\P(x=14)=0.027\\\\\\P(X>14)=1-0.005=0.995

c) Using the probabilities calculated in the point b, we  have:

P(X

d) The probabilities that more than 24 enroll in college is:

P(X>24)=\sum_{25}^{29}P(X=k_i)\\\\\\ P(x=25) = \dbinom{29}{25} p^{25}(1-p)^{4}=23751*0*0.015=0.007\\\\\\P(x=26) = \dbinom{29}{26} p^{26}(1-p)^{3}=3654*0*0.043=0.002\\\\\\P(x=27) = \dbinom{29}{27} p^{27}(1-p)^{2}=406*0*0.123=0\\\\\\P(x=28) = \dbinom{29}{28} p^{28}(1-p)^{1}=29*0*0.35=0\\\\\\P(x=29) = \dbinom{29}{29} p^{29}(1-p)^{0}=1*0*1=0\\\\\\\\P(X>24)=0.007+0.002+0+0+0=0.009

6 0
2 years ago
Explain how finding 4 times 384 can help you find 4 times 5384.then find both products
forsale [732]

Answer:

Given the following: 4 times 384 can help you find 4 times 5384.

4 \times 384 = 1536                

Now, find 4 \times 5384

Using Distributive property: a\cdot (b+c) = a\cdot b + a\cdot c

We can write 4 \times 5384 as

4 \times (5000+384)

Apply distributive property we have;

4 \times 5000 + 4\times 384

Now, find both products;

we know:  4 \times 384 = 1536            

20000 + 1536 = 21,536


8 0
3 years ago
Which of the following best describes the graph below?
docker41 [41]
<h3>Answer:  B.) it is a one-to-one function</h3>

Explanation:

It's a function because it passes the vertical line test. It's also one-to-one because it passes the horizontal line test.

The vertical line test is where we try to draw a single line through more than one point on the blue curve. Such a task isn't possible in this case, and we consider the curve passing the vertical line test. The horizontal line test is nearly identical, but we're dealing with horizontal lines of course.

5 0
2 years ago
There are 12 jurors sitting in a circle
STALIN [3.7K]
I believe you are asking in how many ways they can sit. If so:
The 1st can sit anywhere: he has only 1 way to sit
The 2nd can sit in 11 ways, since one seat is already occupied
The 3rd can sit in 10 ways, since 2 seat are already occupied
The 4th can sit in 9 ways, since 3 seat are already occupied
The 5th can sit in 8 ways, since 4 seat are already occupied
--------------------------------------------------------------------------------
The 12th can sit in 1 way, since11 seat are already occupied
General formula for a circular table:

Number of ways they n persons can be seated: (n-1)!
and the 12 can be seated in (12-1)! = 11! = 39,916,800 ways.
This is called circular permutation
3 0
3 years ago
Find the area of the triangle
olchik [2.2K]

Answer:

4.5

Step-by-step explanation:

1/2 times base times height

( Area of a triangle )

1/2(3)(3)

=4.5

6 0
2 years ago
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