To find this answer :
Step 1: Simplify both sides of the equation.
1/6x=-13
Step 2: Multiply both sides by 6.
6*(1/6x)=(6)*(-13)
You will get x=-78.
Using <span>De Moivre's formula
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if z = a ( cos x + i sin x ) ⇒⇒⇒ ∴ z^n = a^n ( cos nx + i sin nx)
Part (1)
∴ [ 3 (cos 27° + i sin 27°) ]⁵ = (3⁵) ( cos 5*27° + i sin 5*27°)
= 243 ( cos 135° + i sin 135°) ⇒⇒⇒⇒ Polar form
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Part (2)
The angle 135° in the second quadrant ⇒ sin is (+) and cos is (-)
and its reference angle = 180° - 135° = 45°
sin 45° = cos 45°= 1/√2 = (√2)/2
∴ sin 135° = (√2)/2 and cos 135° = -(√2)/2
∴ 243 ( cos 135° + i sin 135°) = 243 [ -(√2)/2 + i (√2)/2 ]
= - 243(√2)/2 + 243 (√2)/2 i ⇒⇒⇒⇒ standard form
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The correct answers are options (1) and (3)
option (1) ⇒⇒⇒ 243 ( cos 135° + i sin 135°) ⇒⇒⇒⇒ Polar form
option (3) ⇒⇒⇒ - 243(√2)/2 + 243 (√2)/2 i ⇒⇒⇒⇒ standard form
Function 1 is a constant function
.. y = 2
Function 2 has the value 3 at x=0.
3 is greater than 2, so Function 2 has the greater initial value.
Answer:
C
It's between C and D.
But when you closely look at the two answer choices, it is C.
Step-by-step explanation:
In D, the angle AC∠ is too small and it can be automatically crossed out. As well as A and B.
Hope this helped!