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Andru [333]
4 years ago
11

What's the difference?

Mathematics
1 answer:
Komok [63]4 years ago
3 0
\bf \begin{cases}
(-2x^2)\\
-2x^2
\end{cases}\qquad (-2x^2)-(-2x^2)\implies -2x^2+2x^2\implies ? you tell us
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What's the answer to x÷6=-13
Mariulka [41]

To find this answer :

Step 1: Simplify both sides of the equation.

1/6x=-13

Step 2: Multiply both sides by 6.

6*(1/6x)=(6)*(-13)

You will get x=-78.

8 0
4 years ago
In order to determine if a home is fairly priced or not it is important to look at the home's
Aleks04 [339]
Price per square foot #apex
8 0
4 years ago
Read 2 more answers
Evaluate the following in polar and standard forms. Select all answers that apply. [3(cos(27°) isin(27°))]^5
Roman55 [17]
Using <span>De Moivre's formula
</span>
if z = a ( cos x + i sin x ) ⇒⇒⇒ ∴ z^n = a^n ( cos nx + i sin nx)

Part (1) 
∴ [ 3 (cos 27° + i sin 27°) ]⁵ = (3⁵) ( cos 5*27° + i sin 5*27°)
= 243 ( cos 135° + i sin 135°)  ⇒⇒⇒⇒ Polar form
=================================
Part (2)

The angle 135° in the second quadrant ⇒ sin is (+)  and cos is (-)
and its reference angle = 180° - 135° = 45°
sin 45° = cos 45°= 1/√2 = (√2)/2
∴ sin 135° = (√2)/2    and  cos 135° = -(√2)/2
∴ 243 ( cos 135° + i sin 135°) = 243 [ -(√2)/2 + i (√2)/2 ]

= - 243(√2)/2 + 243 (√2)/2 i ⇒⇒⇒⇒ standard form
===========================================
The correct answers are options (1) and (3)

option (1) ⇒⇒⇒ 243 ( cos 135° + i sin 135°)  ⇒⇒⇒⇒ Polar form  
option (3) ⇒⇒⇒ - 243(√2)/2 + 243 (√2)/2 i     ⇒⇒⇒⇒ standard form

7 0
4 years ago
PLEASE HELP ASAP 20 POINTS!!!
Olenka [21]
Function 1 is a constant function
.. y = 2

Function 2 has the value 3 at x=0.

3 is greater than 2, so Function 2 has the greater initial value.
7 0
3 years ago
HELP!!!.....I’m stressed
yuradex [85]

Answer:

C

It's between C and D.

But when you closely look at the two answer choices, it is C.

Step-by-step explanation:

In D, the angle AC∠ is too small and it can be automatically crossed out. As well as A and B.

Hope this helped!

7 0
4 years ago
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