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2 years ago

PLEASE SOLVE THIS FAST 6x=10x+4

Mathematics

2 answers:

geniusboy [140]2 years ago

8 0

6x=10x+4
-4x=4, divide both sides by -4
x=-1

LenKa [72]2 years ago

4 0

You would want to subtract 10x from 6x to get -4x and then you divide 4 by -4 to get -1 so x=-1

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What is the solutions to 0=x^2-x-6<br> two things <br> ,,quadratic equationz,,,

natita [175]

Answer:

x1=3. x2=-2

Step-by-step explanation:

$x = \frac{ - b + - \sqrt{b {}^{2} - 4ac } }{2a}$

b=-1

a=1

c=-6

$x = \frac{ - ( - 1) + - \sqrt{ {( - 1)}^{2} - 4 \times 1 \times ( - 6) } }{2 \times 1}$

$x = \frac{1 + - \sqrt{1 + 24} }{2}$

$x = \frac{1 + - \sqrt{25} }{2}$

$x1 = \frac{1 + 5}{2}$

$x2 = \frac{1 - 5}{2}$

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3 0

2 years ago

Helppppppppppppppppppp please

Svetlanka [38]

Answer:

$\sqrt[]{\frac{x+8}{4}}-3$

Step-by-step explanation:

$g(x)=4(x+3)^2-8$

First rewrite $g(x)$ as y

$y=4(x+3)^2-8$

Now swap y and x

$x=4(y+3)^2-8$

Add 8 on both sides.

$x+8=4(y+3)^2-8+8$

$x+8=4(y+3)^2$

Divide by 4.

$\frac{x+8}{4} =\frac{4(y+3)^2}{4}$

$\frac{x+8}{4}=(y+3)^2$

Extract the square root on both sides.

$\sqrt[]{\frac{x+8}{4}}=\sqrt[]{(y+3)^2}$

$\sqrt[]{\frac{x+8}{4}}=y+3$

Subtract 3 on both sides.

$\sqrt[]{\frac{x+8}{4}}-3=y+3-3$

$\sqrt[]{\frac{x+8}{4}}-3=y$

4 0

3 years ago

Solve for g.<br><br> 8g + 3 = –6g + 13g + 13

pav-90 [236]

Answer: g = 10

Step-by-step explanation: 8g + 3 = –6g + 13g + 13

8g + 3 = (–6g + 13g) + (13)

8g + 3 = 7g + 13

8g + 3 - 7g = 7g + 13 - 7g

g + 3 = 13

g + 3 - 3 = 13 - 3

g = 10

3 0

3 years ago

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What is blank divided by 9 equals 5

Rudik [331]

Answer:

45 divided by 9 equals 5

Step-by-step explanation:

4 0

3 years ago

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5/6-3/8=please help me

Yakvenalex [24]

$\frac{5}{6}-\frac{3}{8}=\\
\frac{20}{24}-\frac{9}{24}=\\
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8 0

3 years ago