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3 years ago

Please help hdhdhdhd

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

5 0

109.99*1.065
177.14

Hope this helps :)

ElenaW [278]3 years ago

5 0

Answer:

7tot7347nv47 v37 v7 v7 v v 7v7 v 75 75v7 75v7 v575v5v5 v5v 75v

Step-by-step explanation:

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yulyashka [42]

Answer: A. 90° clockwise, E. 270° Counterclockwise

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2 years ago

The decimal form 1.46 becomes _______ expressed as a percent.

Ann [662]

146% you either multiply the decimal by 100 or just move the decimal place 2 places to the right

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3 years ago

What numbers are mulitply and equals negative 30 and when add equals to negative 25

timofeeve [1]

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3 years ago

A six-sided dice is rolled twice. Find the probability that the larger of the two rolls was equal to 5.

Diano4ka-milaya [45]

The probability that the larger of the two rolls was equal to 5 is; 2/9

<h3>Probability of possible outcomes</h3>

The total number of possible outcomes when the dice is rolled twice is 36 outcomes.

Now, for the larger of the two rolls to equal 5, the total number of favourable outcomes are 8 which are;

(1, 5), (2, 5), (3, 5), (4, 5), (5, 1), (5, 2), (5, 3), (5,4)

Thus, probability that the larger of the two rolls was equal to 5 is;

P(larger of 2 rolls equals 5) = 8/36 = 2/9

Read more about probability of possible outcomes at; brainly.com/question/19916581

8 0

2 years ago

6.) Alan, Becky, Jesus, and Mariah are four students in the chess club. If two of these students will be selected to represent t

Artist 52 [7]

Let's begin by listing out the information given to us:

There are four students: n = 4

Number of students to be selected: r = 2

To calculate the combination of 2 students to be chosen, we use:

$\begin{gathered} ^4C_2=\frac{n!}{(n-r)!}=\frac{4!}{(4-2)!}=\frac{4!}{2!} \\ ^4C_2=\frac{4\cdot3\cdot2\cdot1}{2\cdot1}=\frac{4\cdot3}{1}=12 \\ ^4C_2=12 \end{gathered}$

Therefore, there 12 possible combinations from these

3 0

1 year ago