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Sever21 [200]
2 years ago
5

6973x63 pls explain how u did it!

Mathematics
1 answer:
Goryan [66]2 years ago
4 0

Answer:

4,39299

Step-by-step explanation:

I multiplied 3 x all the numbers in 6,973, then 6 x all the numbers (I added a 0 before I multiplied, then added both the products and got my answer.

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The running back for the Bulldogs football team carried the ball 7 times for a total loss of 15 3 4 yards. Find the average chan
OLga [1]

The average would be the total yards divided by the number of carries:

Rewrite 15 3/4 as 63/4

Now divide by 7:

63/4 / 7 =

63/4 x 1/7 = 63/28 = 2 1/4

Because the total yards was a loss, which would be a negative number, the average is - 2 1/4 yards per play.

4 0
3 years ago
Find the value of x and y
Romashka [77]

Step-by-step explanation:

\triangle ABC \sim\triangle DEF..(Given)  \\ \therefore \frac{AB}{DE} =\frac{BC}{EF}=\frac{AC}{DF}..(CSST)\\\\\therefore \frac{6}{4} =\frac{7}{x}=\frac{8}{y}\\\\ \therefore \frac{6}{4} =\frac{7}{x} \\ \therefore \: x =  \frac{7 \times 4}{6}  \\  \\\therefore \: x =  \frac{28}{6} =  \frac{14}{3}    \\  \\ \huge \red{ \boxed{ \therefore \: x =  \frac{14}{3} }} \\   \\  \because \: \frac{6}{4} =\frac{8}{y} \\  \\ \therefore \:y =  \frac{4 \times 8}{6}  \\  \\ \therefore \:y =  \frac{32}{6}  \\  \\ \huge \purple{ \boxed{ \therefore \:y =  \frac{16}{3}  }}\\  \\

6 0
3 years ago
Which situation is most likely to have a constant rate of change?
lutik1710 [3]

Answer: A. Ounces of water consumed compared with the number of same-size bottles drunk  



Step-by-step explanation:

When a quantity changes uniformly with respect to the change of other quantity, then we say there is a constant rate of change.

Thus, if one quantity is directly proportional to the other quantity then there is constant rate of change.

A. Ounces of water consumed is directly proportional to the number of same-size bottles drunk. Hence there is a constant rate of change of ounces water with respect to the number of same-sized bottles.

Rest of other options do not have directly proportionality relation between the quantities.

8 0
3 years ago
Find the values of A & B so that x^4+x^3+ax+b is divisible by x^2+1
DaniilM [7]

Answer:

a = 1 b = -1.

Step-by-step explanation:

Suppose the quotient when you divide x^4+x^3+ax+b  by x^2 + 1 is

x^2 + ax + b then expanding we have:

(x^2 + 1)(x^2 + ax + b)

= x^4 + ax^3 + bx^2 + x^2 + ax + b

= x^4 + ax^3 + (b + 1)x^2 + ax + b Comparing this with the original expression:

  x^4 +  x^3  + 0 x^2       + ax + b  Comparing coefficients:

a = 1 and b+ 1 = 0 so b = -1.

6 0
3 years ago
What is the next step in solving 0 = x2 + 6x – 10 by completing the square, after you cut 6 in half?
Lynna [10]

Answer:

see below

Step-by-step explanation:

0 = x^2 + 6x – 10

Add 10 to each side

10 = x^2-6x

Take the coefficient of x

-6

Divide by 2

-6/2 =-3

Square it

(-3)^2 =9

Add 9 to each side

10+9 = x^2-6x+9

We use -3 for the square term

19 = (x-3)^2

Take the square root of each side

±sqrt(19) = x-3

Add 3 to each side

3±sqrt(19) = x

6 0
3 years ago
Read 2 more answers
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