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Goryan [66]
4 years ago
9

Yasmin bought 4braclets each bracelet cost $3

Mathematics
1 answer:
Fynjy0 [20]4 years ago
6 0
4 x 3= 12

The 4 bracelets have a total cost of 12 dollars.
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Mrs. Eraca gives this cute dog 4.5 treats that cost $3.59 per treat. How much total money does she spend on this mooching pooch?
kozerog [31]

Answer:

$16.16

Step-by-step explanation:

multiply the amount of treats by the cost of each treat.

4.5 × 3.59 = 16.155.

rounded up gives you $16.16

1 = 3.59

2= 7.18

3= 10.77

4= 14.36

half or .5 of 3.59 is 1.795

14.36 + 1.795 = 16.155 = rounded up $16.16

4 0
3 years ago
Which represents the solution set of inequality 5x-9 <21
Crank

Answer:

x

All real numbers less than 6

Step-by-step explanation:

we have

5x-9

Adds 9 both sides

5x-9+9

5x

Divide by 5 both sides

x

the solution is the interval ---------> (-∞,6)

All real numbers less than 6

see the attached figure to better understand the problem

5 0
4 years ago
Read 2 more answers
Sally has 123 books she divided them into 10 groups how many are in each group?
mariarad [96]

Answer:

12 remainder 3 (or 12.3)

Step-by-step explanation:

123/10=12.3

you can't really have .3 of a book, so 12 remainder 3 or three groups of 13 and 7 groups of 12.

7 0
2 years ago
Simplify to create an equivalent expression.
vitfil [10]
Choice A is your answer.
3 0
4 years ago
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Prove the Triangle Proportinality Theorem
Xelga [282]

Answer:

Step-by-step explanation:

Given: DE║BC

To prove: \frac{\text{AD}}{\text{DB}}=\frac{\text{AE}}{\text{EC}}

                Statements                           Reasons

1). DE║BC                                   1). Given

2). ∠1 ≅ ∠4, ∠3 ≅ ∠4                2). Corresponding angles theorem

3). ΔADE ~ ΔABC                      3). AA Similarity theorem

4). \frac{\text{AB}}{\text{AD}}=\frac{\text{AC}}{\text{AE}}                                4). Corresponding sides are proportional

5). \frac{\text{AD+DB}}{\text{AD}}=\frac{\text{AE+EC}}{AE}                   5). Segment addition postulate

6). 1+\frac{\text{DB}}{\text{AD}}=1+\frac{\text{EC}}{\text{AE}}                   6). \frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}

7). \frac{\text{DB}}{\text{AD}}=\frac{\text{EC}}{\text{AE}}                                7). Subtract 1 from both sides

8). \frac{\text{AD}}{\text{DB}}=\frac{\text{AE}}{\text{EC}}                               8). Take the reciprocal of both sides

5 0
3 years ago
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