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natima [27]
3 years ago
9

Factor the expression 18x+3 using the GCF.

Mathematics
1 answer:
weqwewe [10]3 years ago
8 0
3(6x+1) I’m not sure but probably this could be right
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Benjamin threw a rock straight up from a cliff that was 48 ft above the water. If the height of the rock​ h, in​ feet, after t s
fomenos

Answer: It will take 4 seconds  for the rock to hit the​ water.

Step-by-step explanation:

Given : Benjamin threw a rock straight up from a cliff that was 48 ft above the water.

If the height of the rock​ h, in​ feet, after t seconds is given by the equation

h = -16 t^2+ 52 t + 48

To find : Time taken for the rock to hit the​ water.

When rock hit the water height becomes zero , i.e. put h = 0 , we get

-16 t^2+ 52 t + 48 =0

Divide equation by 2 , we get

-8t^2+26t+24=0

The Laue of x for ax²+bx+c =0 is x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

So , t=\frac{-26\pm\sqrt{(26^{2}-4(-8)(24))}}{2(-8)}

t=\dfrac{-26\pm 38}{-16}\\\\ t=-\dfrac{-26+38}{-16}=-0.75\ \ t=\dfrac{-26-38}{-16}=4

Since t cannot be negative , so t= 4

Hence, it will take 4 seconds  for the rock to hit the​ water.

5 0
3 years ago
A heavy rope, 30 ft long, weighs 0.4 lb/ft and hangs over the edge of a building 80 ft high. Approximate the required work by a
gizmo_the_mogwai [7]

Answer:

180 fb*lb

45 ft*lb

Step-by-step explanation:

We have that the work is equal to:

W = F * d

but when the force is constant and in this case, it is changing.

 therefore it would be:

W = \int\limits^b_ a {F(x)} \, dx

Where a = 0 and b = 30.

F (x) = 0.4 * x

Therefore, we replace and we would be left with:

W = \int\limits^b_a {0.4*x} \, dx

We integrate and we have:

W = 0.4 / 2 * x ^ 2

W = 0.2 * (x ^ 2) from 0 to 30, we replace:

W = 0.2 * (30 ^ 2) - 0.2 * (0 ^ 2)

W = 180 ft * lb

Now in the second part it is the same, but the integral would be from 0 to 15.

we replace:

W = 0.2 * (15 ^ 2) - 0.2 * (0 ^ 2)

W = 45 ft * lb

6 0
3 years ago
Please take a look at the picture.
jenyasd209 [6]

Answer:

B, and A

Step-by-step explanation:

big brain time

3 0
3 years ago
Read 2 more answers
Someone help me please :)
Montano1993 [528]

Answer:

sorry kid idontknow

Step-by-step explanation:

5 0
3 years ago
50 points.
Sphinxa [80]

Answer:

1

Step-by-step explanation:

Using the rules of exponents

(a^m)^{n} = a^{mn}

a^{m} × a^{n} = a^{(m+n)}

Given

(\frac{1}{x^{(a-b)}) } ^{a+b} × (\frac{1}{x^{b+a}) } ^{b-a}

= \frac{1}{x^{(a-b)(a+b)} } × \frac{1}{x^{(b+a)(b-a)} }

= \frac{1}{x^{(a^2-b^2)} } × \frac{1}{x^{(b^2-a^2)} }

= \frac{1}{x^{(a^2-b^2+b^2-a^2)} }

= \frac{1}{x^{0} }

= \frac{1}{1}

= 1

5 0
3 years ago
Read 2 more answers
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