Write in standard form: a line through the origin with slope 2/3
2 answers:
Answer:
2x - 3y = 0
Step-by-step explanation:
the equation of a line passing through the origin is
y = mx ( m is the slope )
here m = , then
y = x ( multiply through by 3 to clear the fraction )
3y = 2x
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
rearranging the above equation into this form
2x = 3y ( subtract 3y from both sides )
2x - 3y = 0 ← in standard form
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Answer:
(x-8)(x+7)
Step-by-step explanation:
using quadratic formula we have
x=
we have:
x^2-x-56=0
a= 1 b=-1 c=-56
so we have:
x=(-(-1)+-sqrt(1^1-4*(1)*(-56)))/(2*1)
x=1+-sqrt(1-4*(-56))/(2)
x=(1+-sqrt(225))/2
x=(1+-15)/2
so we have the roots:
x1=(1+15)/2 =8
x2=(1-15)/2=-7
so the answer is (x-8)(x+7)