What is the smallest whole number larger than the perimeter of any triangle with a side of length 55 and a side of length 1919
1 answer:
Answer:
If the third side is x, then
The perimeter is 5+19+x.
But every side must be less than the sum of the other
two sides, so x < 5+19
x < 24
Adding 5+19 to both sides to make the left side
equal to the perimeter
perimeter = x+5+19 < 24+5+19 = 48
So 48 is the smallest whole number that is larger than the
perimeter of any triangle with a side length of 5 and a side
length of 19.
Step-by-step explanation:
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