Step-by-step explanation:
a = original number of adult tickets
c = original number of child tickets
a/c = 2/5
a = 2c/5
(a+70)/(c+300) = 1/3
(2c/5 + 70)/(c + 300) = 1/3
2c/5 + 70 = (c + 300)/3
2c + 350 = 5(c + 300)/3
6c + 1050 = 5(c + 300) = 5c + 1500
c = 450
a = 2c/5 = 2×450/5 = 2×90 = 180
Joshua sold therefore in total
180 + 70 = 250 adult tickets.
and by the way
450 + 300 = 750 child tickets.
Are the directions asking you to solve these ?
Answer:
80 is the measure because if aob is 40 then doe is 40 and dof is 120 minus the doe that 40 then you are going to get the mesuare which is 80
F(3) = t4(3) = 2
The value of the function at the point of expansion is the first (constant) term of the Taylor series.
