Divide both sides by 2<span>πh:-
r = S / 2</span><span>πh Answer</span>
Answer:
A = (2p + 9) (2p - 9)
B = (x - 9) (x - 4)
Step-by-step explanation:
For A : Rewrite 4p^2 as (2p)^2.
(2p)^2−81
Rewrite 81 as 9^2.
(2p)^2−9^2
Since both terms are perfect squares, factor using the difference of squares formula, a^2 − b^2 = ( a + b ) ( a − b ) where a = 2p and b = 9 .
(2p + 9) (2p − 9)
For B : Consider the form x^2 + bx + c . Find a pair of integers whose product is c and whose sum is b . In this case, whose product is 36 and whose sum is − 13 .
-9, -4
(x - 9) (x - 4)
I hope this helps.
It's sometimes true.
One example is the least common multiple of 2 and 3 is 6, which is their product.
But the product isn't always the answer because (example 2:) the least common multiple of 6 and 10 is 30 because 6*5=30 and 3*10=30, however 6*10 is 60.
Ergo, it is only sometimes true.
Step-by-step explanation:
L = 2W - 8
P = 230 yd
P = 2×(L+W)
230 = 2× (2W - 8 + W)
230 = 2× (3W-8)
230 = 6W-16
6W= 230+16
6W = 246
W = 246/6
W = 41
L = 2(41) -8
= 82-8
= 74
so, the dimensions of the playing field:
the length = 74 yd
the length = 74 ydthe wide = 41 yd
I rounded it and the answer is 400
