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2 years ago

12

Is the square root of 400 rational or irrational

2 answers:

STatiana [176]2 years ago

6 0

Rational number, because the Square root of 400 is 20, since 20 x itself is 400. Hope this helps!

Alex_Xolod [135]2 years ago

3 0

The square root of 400 is rational because the product is 20 which is a whole number making it a rational number

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Emily and her children went into a grocery store and she bought $20.80 worth of bananas and peaches. Each banana costs $0.80 and

MakcuM [25]

Answer:

The number of bananas that Emily bought was 6 and the number of peaches that Emily bought was 8

Step-by-step explanation:

<u><em>The complete question is</em></u>

Emily and her children went into a grocery store and she bought $20.80 worth of bananas and peaches. Each banana costs $0.80 and each peach costs $2. She bought a total of 14 peaches and bananas altogether. Determine the number of peaches and the number of bananas that Emily bought

Let

x ----> the number of bananas that Emily bought

y ----> the number of peaches that Emily bought

we know that

She bought a total of 14 bananas and peaches altogether

so

$x+y=14$ -----> equation A

She bought $20.80 worth of bananas and peaches

so

$0.80x+2y=20.80$ -----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (6,8)

see the attached figure

therefore

The number of bananas that Emily bought was 6 and the number of peaches that Emily bought was 8

3 0

3 years ago

What is the equation of a horizontal line that has a y-intercept of -5?

Cloud [144]

Check the picture below.

6 0

2 years ago

A=1/2bh , solve for b

anygoal [31]

B= the base of the object

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2 years ago

Read 2 more answers

Explain how to write a quadratic equation given the following three points on the graph (5,31) (3,11) (0,11)

masha68 [24]

Given:

The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).

To find:

The equation of the quadratic function.

Solution:

A quadratic function is defined as:

$y=ax^2+bx+c$ ...(i)

It is passes through the point (0,11). So, substitute $x=0,y=11$ in (i).

$11=a(0)^2+b(0)+c$

$11=c$

Putting $c=11$ in (i), we get

$y=ax^2+bx+11$ ...(ii)

The quadratic function passes through the point (5,31). So, substitute $x=5,y=31$ in (ii).

$31=a(5)^2+b(5)+11$

$31-11=a(25)+5b$

$20=25a+5b$

Divide both sides by 5.

$4=5a+b$ ...(iii)

The quadratic function passes through the point (3,11). So, substitute $x=3,y=11$ in (ii).

$11=a(3)^2+b(3)+11$

$11-11=a(9)+3b$

$0=9a+3b$

Divide both sides by 3.

$0=3a+b$ ...(iv)

Subtracting (iv) from (iii), we get

$4-0=5a+b-3a-b$

$4=2a$

$\dfrac{4}{2}=a$

$2=a$

Putting $a=2$ in (iv), we get

$0=3(2)+b$

$0=6+b$

$-6=b$

Putting $a=2,b=-6$ in (ii), we get

$y=(2)x^2+(-6)x+11$

$y=2x^2-6x+11$

Therefore, the required quadratic equation is $y=2x^2-6x+11$ .

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rodikova [14]

Multiply 47x22 and you'll get a total of 1034 prizes

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2 years ago