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alexdok [17]
2 years ago
5

Hi pls help me tysm :)​

Mathematics
1 answer:
prisoha [69]2 years ago
7 0

Answer:

80.78°

Step-by-step explanation:

When the 30 cm long string will be bent in the form of a sector it's two sides will be radii of the sector and lower part be the arc. Length of the arc can be found as given below.

Length of the string = 30 cm

radius of sector (r)= 8.8 cm

Length of the arc (l) = 30 - 2*8.8 = 30 - 17.6 = 12.4 cm

Let the sector makes \theta angle at the centre of the circle.

Formula for length of arc of a sector is given as:

\huge \red{l=\frac{\theta}{360\degree}\times 2\pi r}

Plugging the values of l and r in the above formula, we find:

12.4 =  \frac{ \theta}{360 \degree}  \times 2(3.14)(8.8) \\  \\\implies12.4 =  \frac{ \theta}{360 \degree}  \times 55.264 \\  \\  \implies \:  \theta =  \frac{12.4 \times 360 \degree}{55.264}  \\  \\ \implies \:  \theta =80.775 \degree \\  \\ \implies \:  \theta  \approx \: 80.78 \degree

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I know you want to answer this question.
Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

\frac{1}{2} ^{x-4} - 3 = 4^{x-3} - 2

First, convert 4^{x-3} to base 2:

4^{x-3} = (2^{2})^{x-3}

\frac{1}{2} ^{x-4} - 3 = (2^{2})^{x-3} - 2

Next, convert \frac{1}{2} ^{x-4} to base 2:

\frac{1}{2} ^{x-4} = (2^{-1})^{x-4}

(2^{-1})^{x-4} - 3 =  (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{-1})^{x-4} = 2^{-1*(x-4)}

2^{-1*(x-4)} - 3 = (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{2})^{x-3} = 2^{2(x-3)}

2^{-1*(x-4)} - 3 = 2^{2(x-3)} - 2

Apply exponent rule: a^{b+c} = a^{b}a^{c}:

2^{-1(x-4)} = 2^{-1x} * 2^{4}, 2^{2(x-3)} = 2^{2x} * 2^{-6}

2^{-1 * x} * 2^{4} - 3 = 2^{2x} * 2^{-6} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

2^{-1x} = (2^{x})^{-1}, 2^{2x} = (2^{x})^{2}

(2^{x})^{-1} * 2^{4} - 3 = (2^{x})^{2} * 2^{-6} - 2

Rewrite the equation with 2^{x} = u:

(u)^{-1} * 2^{4} - 3 = (u)^{2} * 2^{-6} - 2

Solve u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2:

u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2

Refine:

\frac{16}{u} - 3 = \frac{1}{64}u^{2} - 2

Add 3 to both sides:

\frac{16}{u} - 3 + 3 = \frac{1}{64}u^{2} - 2 + 3

Simplify:

\frac{16}{u} = \frac{1}{64}u^{2} + 1

Multiply by the Least Common Multiplier (64u):

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify:

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify \frac{16}{u} * 64u:

1024

Simplify \frac{1}{64}u^{2} * 64u:

u^{3}

Substitute:

1024 = u^{3} + 64u

Solve for u:

u = 8

Substitute back u = 2^{x}:

8 = 2^{x}

Solve for x:

x = 3

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4 years ago
Convert to an improper fraction. Type in your answer with the negative in the numerator. -8 3/4 =
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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