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1 answer:
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Answer :
The proof is as follows :
Step-by-step explanation:
Let NC = x
⇒ AB = 3x and AN = 2x
In Δ ABN, By using Pythagoras theorem,
AB² = BN² + AN²
⇒ BN² = AB² - AN²
⇒ BN² = (3x)² - (2x)²
⇒ BN² = 5x²
⇒ BN = x√5 .......................(1)
Now in ΔANC , Using Pythagoras theorem We have,
AC² = NC² + AN²
⇒ AC² = x² + (2x)²
⇒ AC² = 5x²
⇒ AC = x√5 ....................(2)
From equations (1) and (2) We get,
AC = BN , which is our required result
Given:
The expression is:
To find:
The value of the given expression when and
.
Solution:
We have,
Putting and
, we get
It can be written as
Therefore, the value of the given expression when
and
.
<em>Subtract</em> 2/3x on both sides.
Combine 5/3x and -2/3x to get x.
Subtract 4 from both sides. <em>Any value</em> subtracted from zero results in its negative value.
