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2 years ago

Choose the equation for the line in slope-intercept form. help.

Mathematics

1 answer:

olga55 [171]2 years ago

6 0

analyze picture

y int is -3

slope is

1/2

so, the equation is 1/2x-3,

which is number three

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A scientist raised $32,506 for his project. He later found out that he would need $57,500 to completely pay for it. How much mor

hammer [34]

We need to subtract: the scientist needed 57,500 dollars, but already had 32,506, so we need to find what's left: 57,500 - 32,506 = 24,992 dollars

Your answer is A. Hope that helps! :)

3 0

3 years ago

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It's easy math but I am not very good at it, I need some help. can someone help me????? solve all 3of them please!

jonny [76]

Answer:

1. 458 - 247 = 211

2. 58.92 - 43.87 = 15.05

3. 51/8 - 15/8 = 4.5

Here you go ! Hope this helps !

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3 years ago

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Two rays that intersect at their initial point.

dolphi86 [110]

That is called an angle.

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3 years ago

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How do you rationalize the numerator in this problem?

maw [93]

To solve this problem, you have to know these two special factorizations:

$x^3-y^3=(x-y)(x^2+xy+y^2)\\ x^3+y^3=(x+y)(x^2-xy+y^2)$

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:

$\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y$

That tells us that we have:

$\frac{x-y}{h}$

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

$\frac{x-y}{h}*\frac{x^2+xy+y^2}{x^2+xy+y^2}=\frac{x^3-y^3}{h*(x^2+xy+y^2)}$

So, we have:

$\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}$

That is our rational expression with a rationalized numerator.

Also, you could just mutiply by:

$\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}$

Either way, our expression is rationalized.

7 0

3 years ago

Find the diameter of the base of a right cylinder if the surface area is 128(pi) and the height is 12cm.

Gelneren [198K]

$d=2r\\
A=128 \pi \\
A=2 \pi r^{2} +2 \pi rh \\\\
2 \pi r^{2} +2 \pi rh = 128 \pi \\
2 r^{2} +2rh = 128\\
2 r^{2}+24r-128=0\\
r^{2}+12r-64=0\\
delta=400\\
r_{1/2} = -16/4 \\
r=4cm\\
d=8cm\\
$

Radius / diameter as a length cannot be negative, that's why '-16' is wrong.

8 0

3 years ago