Domain and range of the function

Mathematics

1 answer:

amm18124 years ago

4 0

The answer you are looking for is B.

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Two numbers add to 140. If you double the smaller number and halve the larger number, then the two resulting numbers are equal.

iren2701 [21]

Answer:112

Step-by-step explanation:

5 0

3 years ago

PLEASE PLEASE HELP ME OUT ITS URGENT <br><br><br> What are the solutions to the quadratic equation?

mixer [17]

Answer: Choice C) $x = 4\pm2\sqrt{10}$

This is the same as saying $x = 4+2\sqrt{10} \ \ \text{ or } \ \ x = 4-2\sqrt{10}$

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Explanation:

First get everything to one side

x^2 + 13 = 8x + 37

x^2 + 13 - 8x - 37 = 0

x^2 - 8x - 24 = 0

Here we have a quadratic in the form ax^2+bx+c = 0

Note how a = 1, b = -8, c = -24

Those values are plugged into the quadratic formula below

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-8)\pm\sqrt{(-8)^2-4(1)(-24)}}{2(1)}\\\\x = \frac{8\pm\sqrt{160}}{2}\\\\x = \frac{8\pm\sqrt{16*10}}{2}\\\\x = \frac{8\pm\sqrt{16}*\sqrt{10}}{2}\\\\x = \frac{8\pm4*\sqrt{10}}{2}\\\\x = \frac{2(4\pm2\sqrt{10})}{2}\\\\x = 4\pm2\sqrt{10}$

This shows the answer is choice C.

The plus minus breaks down that equation these two solutions

$x = 4+2\sqrt{10} \ \ \text{ or } \ \ x = 4-2\sqrt{10}$

6 0

3 years ago

Read 2 more answers

Given the system of equations. Which of the {-5x+y=6 --> y=5x+6 3x-y=14}

Molodets [167]

The first thing we must do is solve the problem step by step to choose the correct option.
Step 1:
Clear y from the first equation:
-5x + y = 6
y = 5x + 6
Step 2:
Replace this value of y in the second equation:
3x-y = 14
Substituting:
3x- (5x + 6) = 14
answer
the resulting equation after an equivalent expression for y is substituted into the second equation is
3x- (5x + 6) = 14

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3 years ago

Whats -7 x 5? Can you also explain how you did it?

goldenfox [79]

Answer:

-35

Step-by-step explanation:

+ x + = +

- x - = +

- x + = -

hope that helps

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