Answer:
Please check the explanation.
Step-by-step explanation:
Given the function
We know that the domain of the function is the set of input or arguments for which the function is real and defined.
In other words,
- Domain refers to all the possible sets of input values on the x-axis.
Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.
as x³ - 16x ≥ 0
Thus, identifying the intervals:
Thus,
The domain of the function f(x) is:
![x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}](https://tex.z-dn.net/?f=x%5Cleft%28x%2B4%5Cright%29%5Cleft%28x-4%5Cright%29%5Cge%20%5C%3A0%5Cquad%20%3A%5Cquad%20%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3A-4%5Cle%20%5C%3Ax%5Cle%20%5C%3A0%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Ax%5Cge%20%5C%3A4%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%5Cleft%5B-4%2C%5C%3A0%5Cright%5D%5Ccup%20%5C%3A%5B4%2C%5C%3A%5Cinfty%20%5C%3A%29%5Cend%7Bbmatrix%7D)
And the Least Value of the domain is -4.
Answer:
no, they are not functions
Step-by-step explanation:
this is because a single domain has multiple range.
i.e. domain 2 has ranges 2 and 4
Tgα = tan(α) = sqrt(2)/1 = opposite/ adjacent
opposite = sqrt(2)
adjacent = 1
hypotenuse = sqrt(opposite^2 + adjacent^2)
= sqrt(sqrt(2)^2 + 1^2) = sqrt(3)
sin(α) = opposite/hypotenuse
= sqrt(2)/sqrt(3)
cos(α) = adjacent/hypotenuse
= 1/sqrt(3)
now we can calculate the value of
5sin²α+3cos²α / 3sin²α-5cos²α
... do the math
Answer:
It's true
Step-by-step explanation:
f(x) and g(x) are another name to use instead of y
A function is an equation which, for every x, has only one response for y. A function assigns each input of a given form to exactly one output.
Answer:
i can't see it
Step-by-step explanation:
