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Temka [501]
2 years ago
11

The weekly revenue for a company is r=-4p^2+40p+887, where p is the price of the company’s product. Use the discriminant to find

whether there is a price for which the weekly revenue would be $1200
Mathematics
1 answer:
Degger [83]2 years ago
3 0

Answer:

No, there is no price for which the weekly revenue would be 1200

Step-by-step explanation:

If r = 1200

-4p^2+40p+887=1200\\\\\implies -4p^2+40p-313=0

Therefore, a=-4, \ \ \ b=40, \ \ \ c=-313

discriminant = b^2-4ac

\implies 40^2-4(-4)(-313) = 1600 - 5008=-3408\\\\-3408

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The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?
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Step-by-step explanation:

we are given a quadratic function

\displaystyle f(x) =  - 5 {x}^{2}  + 30x - 200

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\displaystyle x _{ \rm  min} =  \frac{ - b}{2a}

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\displaystyle x _{ \rm  min} =  \frac{ - 30}{2. - 5}

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simply division:

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